0, 1, 4, 15, 64, ____
1) 225 2) 325 3) 125 4) None

• answer is 325.
  logic : 0*1+1,1*2+2,4*3+3,15*4+4,64*5+5,.....
  
  
  number*1+1...result*2+2...result*3+3......
• 9 years agoHelpfull: Yes(73) No(2)
• 0,1,4,15,64.....
  0*1+1=1
  1*2+2=4
  4*3+3=15
  15*4+4=64
  64*5+5=325
  
  answer is 325
• 9 years agoHelpfull: Yes(23) No(1)
• what is the remainder when 48^565 divided by 7? todays my tcs question
• 9 years agoHelpfull: Yes(5) No(0)
• 0*1+1=1
  1*2+2=4
  4*3+3=15
  .
  .
  64*5+5=325
• 9 years agoHelpfull: Yes(2) No(0)
• 325..
  no explanation
  
• 9 years agoHelpfull: Yes(1) No(1)
• 0^2=0
  1^2=1
  2^2=4
  4^2-1 =15
  8^2 =64
  16^2-1 =255
• 9 years agoHelpfull: Yes(1) No(0)
• 0,1,4,15,64.....
  0*1+1=1
  1*2+2=4
  4*3+3=15
  15*4+4=64
  64*5+5=325
  
  answer is 325
  
• 9 years agoHelpfull: Yes(1) No(0)
• Let n be the no. of objects.
  By
  V(k,n) = (n*k+1)*(V(k,n-1) + k^n)),
  V(k,0) = 1.
  n>=0
  By changing K's value we get,
  [k=0] 1, 1, 1, 1, 1, 1....
  [k=1] 1, 4, 15, 64, 325, 1956...
  
  Answer -> 2)325.
• 9 years agoHelpfull: Yes(0) No(5)
• answer is 325.
• 9 years agoHelpfull: Yes(0) No(0)
• 64*5+5=325
• 9 years agoHelpfull: Yes(0) No(0)
• 2) 325
  1*2+2=4
  4*3+3=15
  15*4+4=64
  64*5+5=325
• 9 years agoHelpfull: Yes(0) No(0)
• Answer shouls be 325
• 9 years agoHelpfull: Yes(0) No(0)
• 2>
  0*1+1=1
  1*2+2=4
  4*3+3=15 ....And so on..64*5+5=325
• 9 years agoHelpfull: Yes(0) No(0)
• 325
  0,0*1+1,1*2+2,4*3+3,15*4+4,64*5+5
• 9 years agoHelpfull: Yes(0) No(0)
• 0,1,4,15,64.....
  0*1+1=1
  1*2+2=4
  4*3+3=15
  15*4+4=64
  64*5+5=325
  
  answer is 325
• 9 years agoHelpfull: Yes(0) No(0)
• 1*2+2=4
  4*3+3=15
  15*4+4=64
  64*5+5=325
  so ans is 325
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 325.its like 1*2+2,4*3+3,15*4+4,64*5+5
• 9 years agoHelpfull: Yes(0) No(0)
• 0,1,4,15,64.....
  0*1+1=1
  1*2+2=4
  4*3+3=15
  15*4+4=64
  64*5+5=325
  
  answer is 325
  Read more at http://www.m4maths.com/frequently-asked-placement-questions.php?ISSOLVED=&page=1&LPP=10&SOURCE=TCS&MYPUZZLE=&UID=&TOPIC=&SUB_TOPIC=#pO1Gvf4TZ7bD1Xbu.99
• 9 years agoHelpfull: Yes(0) No(0)
• @ pervali yesaswi
  
  Answer for u r question ....
  48^565 / 7 = the number ( 48^565 )
  Base is 48
  Power is 565
  Now, we can write power as 5*113 we can assume that ,
  ( 48^5^113) .
  First step 48^5 = 48*48*48*48*48( multiply all the last digits of the numbers ) which results in (8*8*8*8*8)=(64*64*8) again multiply the last digits....(4*4*8) = 16*8 again last digit 6*8 finally u get 48 .in 48 last digit is 8 make a note of this ...
  Now consider,
  
  48^565=48^5^113=8^113
  Logic= for every five times of 48 multiple we got last digit as 8. 113 has five multiple of about 22 and multiply of 48 for three times ( 113/5= 22 plus 3 as remainder).
  For all the five multiples we can get the last digit as 8.
  
  5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100,105,110
  
  8,8,8,8,8,8,8,8,8,.......so on
  Consider each five multiple as 8. we have 4 five multiples in the above multiple s of five and two are remained called 105,110.
  Till 100= ( we have four multople of 5 multiples of 8 is 8) . hence 48 ^100= 8 is the last digit. And more 13 times we have five multiple is 2 and 3 remains .
  48*48*48*48*48*48*48*48*48*48*48*48*48=[ total 13 times ]…
  For first five times last digit is 8. And next five times also 8. And we have last three times now the final conclusion is
  
  Last digit of 100 times is 8.
  Last digit of five times is 8 and again 8 for next five digits. And finally 3 times 48.
  
  ==(8*8*8*8)*(8*8)*(48*48*48)
  Multiply only last digits
  ==(8*8*8*8)*(8*8)*(8*8*8)
  
  First five 8 are last digit is 8.
  Now = 8*8*8*8*8= last digit is 8.
  
  
  ------- 8/7==remainder 1.
  
  
• 8 years agoHelpfull: Yes(0) No(1)
• 325 :: 4 ka 3 se multiply plus 3 add so we get 15 ! same process with 15 but with multiplier 4 and add 4 ....64*5 plus 5
• 8 years agoHelpfull: Yes(0) No(1)