What is the probability that the sum 9 would appear exactly three times when a pair of dice is rolled four times?

• when two dices are thrown,probability of getting a sum of 9=4/36=1/9
  probability of getting a sum of 9 exactly three times in four times rolling=
  ((1/9)*(1/9)*(1/9)*(8/9)*4)=32/(9^4)=32/6561
  
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• Total Cases = 36
  Prob of appearing sum=9 exactly 3 tomes out of 4 = (4/36)(4/36)(4/36)(32/36)
  =8/(9^4)
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• prob. of getting exactly 9 for 1 time = 1/11
  ans: 3/43
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• plz explain in other way.... in detail...
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