a jogger running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 metres long train running at 45 kmph in the same direction . in how much time will the train pass the jogger ????

• Total Distance(d) = 240+120 = 360 meter
  Relative speed (s) = 45 - 9 = 36 Kmph = 36*5/18 = 10mps
  
  d = s* t
  360 = 10*t
  t = 36 seconds
• 10 years agoHelpfull: Yes(11) No(8)
• time to pass the jogger is=(120+240)/(45-9)=(360/36)*(18/5)=36 minutes
  
• 10 years agoHelpfull: Yes(2) No(4)
• d = s* t
  360 = 10*t
  t = 36 seconds
  
• 10 years agoHelpfull: Yes(1) No(1)
• Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
  
  = 36 x 5 m/sec
  18
  = 10 m/sec.
  
  Distance to be covered = (240 + 120) m = 360 m.
  
  Time taken = 360 sec = 36 sec.
  10
  
• 9 years agoHelpfull: Yes(0) No(0)
• Speed of train relative to jogger =
  (
  45
  −
  9
  )
  km/hr =
  36
  km/hr
  
  =
  (
  36
  ×
  5
  18
  )
  m
  /
  s
  e
  c
  
  
  =
  10
  m/sec.
  
  Distance to be covered =
  (
  240
  +
  120
  )
  m
  =
  360
  m
  .
  
  
  ∴
  Time taken
  =
  (
  360
  10
  )
  s
  e
  c
  =
  36
  s
  e
  c
  .
• 6 Months agoHelpfull: Yes(0) No(0)