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Old women said no of days of my grand daughter = no of months my daughters is?
And my age in no of years is= no of weeks of my grand daughter . sum of their ages is 115. Find d old women age?
Read Solution (Total 18)
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- age of grand daughter is d days d/365 years
and age of daughter is d months d/12yrs
and age of old women is d/7 years
d/7 + d/12 + d/365 = 115years
4380d +2555d + 84d = 115*365*12*7
7019d = 3525900
d = 3525900/7019 = 502
age of old women is 502/7 71.7 years - 10 years agoHelpfull: Yes(46) No(8)
- let x is the no. of days of grand daughter then
x+x*30+x/7 *365=115*365 so x=447.5
so no of year=x/7 =64years
- 10 years agoHelpfull: Yes(19) No(15)
- suppose no of days of grand daughter=x
therefore no of weeks of daughter are=x
no of days of daughter are=30*x (approx.)
weeks of grand daughter=days of grand daughter/7=x/7
therefore age of old women is=x/7 years=365*x/7 days
sum of ages of grand daughter , daughter and old women=(x)+(x*30)+(365*x/7)
=x(1+30+365/7) ......(1)
and given total age is=115 years=115*365 days ......................(2)
therefore
x(1+30+365/7)=115*365
x(83.142)=115*365
x=(115*365)/(83.142)
x=504.85~=505 days (grand daughter's age in days)
grand daughter's age in weeks=505/7=72.14=72
therefore old womens age in years=72 years - 10 years agoHelpfull: Yes(10) No(0)
- let X be the grandchild year
So Daughter of Old Woman Age is 365X/12 Yr (365X month)
Old Woman age is 52X (1year = 52 week)
a to q
X+365x/12+52x=115
after solv X= 1.24
Old Women Age= 1.24*52= 64 year approx - 10 years agoHelpfull: Yes(3) No(3)
- let x is the no. of years of old women.
then
A/Q
x+x/52+7*x/12= 115
on solving we get
x= 71.76yrs - 10 years agoHelpfull: Yes(3) No(0)
- Let x is the age of old woman.
so 365x+7x+30*(7x)=115*365,
After solving x=72.12 years ans=72.12 years - 10 years agoHelpfull: Yes(2) No(0)
- let grand daughter days be x
x365 + x12 + x7=115 yrs
x=73.76=74 yrs (approx) - 10 years agoHelpfull: Yes(1) No(4)
- age of old women is 502/7 71.7 years
- 10 years agoHelpfull: Yes(1) No(0)
- let grand daughtr=x yrs,daughtr=y yrs,grand mother= z yrs
given 365x=y12 and z=52x and x+y+z=115
substitute,we get x=1.3786 then z=71.6 yrs
- 10 years agoHelpfull: Yes(1) No(0)
- we know that , No. of days in year=365
No. of months in year=12
No. of weeks in year= 52
Let, age of grand daughter be X
age of daughter be Y
age of grand mother be Z
Given,
No. of days of grand daughter = No. of months of daughter
i.e., 365X=12Y----------(1)
Age of grand mother in years= No. of weeks of grand daughter
i.e., Z=52X-------------(2)
Sum of their ages=115
i.e., X+Y+Z=115------------(3)
Solving 1,2&3,
X=1.378
Z=52*1.378=71.6years - 6 years agoHelpfull: Yes(1) No(0)
- let z be the age of grand mother in years, then in weeks, she is 52z weeks.
Grand daughter is z weeks. and daughter is 28z weeks.
52z+28z+z=115*52
age of grand mother is approx 73 years - 10 years agoHelpfull: Yes(0) No(0)
- age of grand daughter =x days
age of daughter =x *30 days
age of old women =x/7 yrs=365*x/7 days
x+x*30+365*x/7=115*365
x=504.85
age of old women=504.85/7=72.12=73 yrs - 10 years agoHelpfull: Yes(0) No(0)
- d/360+d/12+d/52(week)=115
d=70 - 10 years agoHelpfull: Yes(0) No(0)
- Solution given by loveneet is absolutely right
- 10 years agoHelpfull: Yes(0) No(0)
- 98 years..
granddau age in days x=y=x/12(mother)
old z/365=x/7(grsnddaughter)
x+y+z=115
- 9 years agoHelpfull: Yes(0) No(1)
- 23v and 32
- 9 years agoHelpfull: Yes(0) No(1)
- let d days is the age of the grand daughter,then
d+30*d+d/7*365 =115*365
solve it
d=504.8539...
age of the grandmother is d/7=72.12
- 8 years agoHelpfull: Yes(0) No(0)
- Sum of their old man is 115 so ans odd number is even so 64
- 8 years agoHelpfull: Yes(0) No(0)
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