Write a program in JAVA which print 0 if 1 is provided as input and print 1 if 0 is provided.
Condition apply :
(i.) you can't use predefined function(like logical not).
(ii.) You can't use if-else condition.

• import java.util.*;
  import java.util.scanner;
  class Program
  {
  public static void main(String args[])
  {
  Scanner sc=new Scanner(System.in);
  int i=sc.nextInt();
  Stirng s=i>0?"0":"1":
  System.out.println(s);
  }
  }
• 9 years agoHelpfull: Yes(26) No(2)
• Lets take n as the input no.
  {
  system.out.println(1-n)
  when nis 1 output is 0 and vice versa
• 9 years agoHelpfull: Yes(26) No(0)
• import java.util.*;
  class a{
  public static void main(Sting args[]){
  try{
  Scanner sc=new Scanner(System.in);
  int a=Integer.parseInt(sc.next());
  switch(a){
  case 0:a=1;System.out.println(" o changes to :"+a);
  System
  break;
  case 1:a=0;System.out.println(" 1 changes to :"+a);
  break;
  default:System.out.println("please enter a valid no:");
  break;
  
  }
  }
  catch(Exception ex){
  System.out.println(ex.getMessage());
  }
  
  }
  
  }
• 9 years agoHelpfull: Yes(5) No(2)
• void main()
  {
  int ch,a;
  printf("enter your choice");
  scanf("%d",&ch);
  switch(ch)
  {
  case 0:a=1;
  printf("%d",a);
  break;
  case 1:a=0;
  printf("%d",a);
  break;
  default:printf("enter 0 or 1 only");
  break;
  }
  }
• 9 years agoHelpfull: Yes(4) No(1)
• using switch cases will work
• 9 years agoHelpfull: Yes(2) No(6)
• class ABC
  {
  
• 9 years agoHelpfull: Yes(0) No(2)
• import java.util.Scanner;
  public class Conversion
  {
  public static void main(String... s)
  { int i;
  Scanner output =new Scanner(System.in);
  System.out.println("enter the value of i either 1 or 0");
  i=output.next();
  switch(i)
  { Case 1: System.out.println("0");
  break;
  Case 0: System.out.println("1");
  break;
  default: System.out.println("wrong value");
  }
  
  }
  }
• 9 years agoHelpfull: Yes(0) No(0)
• /*
  * To change this license header, choose License Headers in Project Properties.
  * To change this template file, choose Tools | Templates
  * and open the template in the editor.
  */
  package tricky.java.program;
  
  import java.util.Scanner;
  
  /**
  *
  * @author vikash
  */
  public class TrickyJavaProgram {
  
  /**
  * @param args the command line arguments
  */
  public static void main(String[] args) {
  // TODO code application logic here
  Scanner reader = new Scanner(System.in); // Reading from System.in
  System.out.println("Enter a number: ");
  int n = reader.nextInt();
  int b=n;
  int a[]= new int[2];
  a[0]=1;
  a[1]=0;
  System.out.println(String.valueOf(a[b]));
  
  }
  
  }
  
• 8 years agoHelpfull: Yes(0) No(0)
• public class Check {
  public static void main(String[] args) {
  int i=1;
  for(;i==1;)
  {
  i++;
  System.out.println("0");
  }
  for(;i==0;)
  {
  i++;
  System.out.println("1");
  }
  
  
  }
  }
  
  
  
  for loop's second segment holds matter of checking and validating expression.. using that idea i ave implemented the program, assigning the other number based on checking and printing the assigned value gets the right answer.
• 5 years agoHelpfull: Yes(0) No(0)
• import java.util.*;
  class solution{
  public static void main(String args[]){
  Scanner sc=new Scanner(System.in);
  int a=sc.nextInt();
  System.out.println(1-a);
  }
  }
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  
  int main() {
  int n,s;
  printf("enter only 0 0r 1 in n value");
  scanf("%d",&n);
  
  s=(n==0?1:0);
  printf("n%d",s);
  
  
  }
• 4 years agoHelpfull: Yes(0) No(0)