There ARE SOME COINS IN THE BAG 1 Ps 5 Ps 10 Ps 25 Ps A person HAS TO DISTRIBUTE

Ans, 49
check for all possible cases
case1: 2 coins of 25--------------- 1
case2: 1 coin of 25-----------------13
case3: 0 coin of 25-----------------1+3+5+7+9+11
9 years agoHelpfull: Yes(5) No(4)

we have to find all possible set of coins, so that every set consist 25 ps (by using 1 Ps,5 Ps,10 Ps,25 Ps).
eg.
25ps 10ps 5ps 1ps

1) 2 0 0 0 =50ps

2) 1 2 1 0 =50ps
3) 1 2 0 1 =50ps
4) 1 1 3 0 =50ps
5) 1 1 2 5 =50ps
.
..
.. and so on.
9 years agoHelpfull: Yes(2) No(0)
ie; 25 ps*2 = 50 paisa
1ps * 50 = 50 paisa
5ps * 10= 50 paisa
10ps* 5= 50paisa
so 4 combination 4 children
9 years agoHelpfull: Yes(1) No(0)
Ans-49
Find the combinations of using only 1 coin(1,5 ,10,25)=4,only 2 coins[(1,5),(1,10),(1,25),(5,10),(5,25),(10,25)]=19,only 3 coins[(1,5,10),(1,10,25),(5,10,25),(1,5,25)]=24,all 4 coins(1,5,10,25)=2
9 years agoHelpfull: Yes(1) No(0)
the answer should be 4
9 years agoHelpfull: Yes(0) No(1)
4 types of coins can be distributed among 4 people only if we have to distribute distinctly as mentioned in the question 'no 2 getting the same denomenaion'
hence answer is 4
9 years agoHelpfull: Yes(0) No(0)
plz explain in detail??
9 years agoHelpfull: Yes(0) No(0)
Plz explain properly
9 years agoHelpfull: Yes(0) No(0)
ashok how 49 come? plz tell us
9 years agoHelpfull: Yes(0) No(0)

There ARE SOME COINS IN THE BAG(1 Ps,5 Ps,10 Ps,25 Ps).A person HAS TO DISTRIBUTE COINS TO TS IN SUCH A WAY THAT EACH ONE GET 50 PAISE exact HAVING NO 2 GETTING THE SAME DENOMINATION OF COINS.THEN HOW MANY CHILDRENS ARE THERE ???