Sharmila has to write an analysis on the cost and speed of 5 cars (A, B, C, D and E) and 3 motorcycles ( P, Q and R). A is
the fastest among the cars and R is the slowest among the motorcycles. C is costlier than D and Q but cheaper than B.
Among the cars, A is not the costliest. D is cheaper than E and there is no car whose cost lies between the cost of these
two. E is faster than three of the cars and all the motorcycles. Q is costlier than R but cheaper than P, which is faster
than Q. Now, based on her analysis, Professor Venkat asks her to verify the following statements and determine which
statement must necessarily be true.
OPTIONS
1) D can be the median value among cars as far as their cost is concerned.
2) If P is costlier than E, exactly 2 cars are cheaper than P.
3) If P is cheaper than A which is not costlier than E, R is the cheapest of all cars and motorcycles put
together.
4) None of the above

• Ans(3)
  According to passage-
  1.COST Q,B>C>(E>D)
  2.COST P>Q>R
  
  According to question
  3.COST A>P
  4.COST (E>D)>p
  
  combining 1 & 4
  
  5. COST Q,B>C>(E>D)>p
  
  combining 4 & 5
  6.COST Q,B,C,E,D,A>p
  
  combining 2 & 6
  Q,B,C,E,D,A>p>Q>R
• 10 years agoHelpfull: Yes(16) No(3)
• As per the question we can arrange the car cost in the following order(on the basis of decreasing cost):
  1. B>C>E>D>A
  2. B>C>A>E>D
  
  For the 2nd option only in the first case the condition will be satisfied, i.e.
  
  if P>E
  and as per the question P>Q>R
  
  so we will have two cars which are cheaper than P i.e. B & C.
  
  But in the 2nd case we will have three cars i.e. B,C & A. So 2nd condition will not be true in every case.
  
  Now consider the 3rd option if PE>D>A>P>Q>R
  So R would be the cheapest of all cars and motorcycles and the the 3rd option will be true.
  
  So Answer of this question is option 3.
• 10 years agoHelpfull: Yes(8) No(0)
• Small Correction...
  
  As per the question we can arrange the car cost in the following order(on the basis of decreasing cost):
  1. B>C>E>D>A
  2. B>C>A>E>D
  
  For the 2nd option only in the first case the condition will be satisfied, i.e.
  
  if P>E and as per the question P>Q>R
  so we will have two cars which are cheaper than P i.e. B & C.
  
  But in the 2nd case we will have three cars i.e. B,C & A. So 2nd condition will not be true in every case.
  
  Now consider the 3rd option if PE>D>A>P>Q>R
  So R would be the cheapest of all cars and motorcycles and the the 3rd option will be true.
• 10 years agoHelpfull: Yes(3) No(1)
• 1-D is not a median value among the cars as far as their cost is concerned
  why because the cost is like
  
  B C E D A
  so 1 is wrong
  and coming to 2nd option
  p is costlier than E,exactly 2 cars are cheaper than p.it is also wrong why because
  if P is costlier than E then the cost of the cars like as
  B C P D A E
  so here P is not a car but as per cost there are 3 cars under the cost of p. so 2nd option is wrong
  coming to 3rd one
  here R is already cheaper on as cost of cars and bike as
  cars cost B C E D A
  bike cost P Q R
  if we change the place of any one of then r is always cheaper one so ans 3 is correct
  ans :: 3
• 10 years agoHelpfull: Yes(2) No(0)
• ANS 3 R
• 10 years agoHelpfull: Yes(1) No(0)
• option 1 coz D is cheaper than E.
• 10 years agoHelpfull: Yes(0) No(5)
• 3
  cost wise order of cars is BCEDPQRA
• 10 years agoHelpfull: Yes(0) No(0)
• car speed car cost bike speed bike cost
  1.A B 1.P 1.P
  2.E C 2.Q 2.Q
  B/C/D n.E 3.R 3.R
  P/Q/R n+1.D
  Q is also cheaper than C
  
  
  In car cost A can be anywhere except 1st position and between E and D.
  If A is cheaper than E then it must be cheaper than D thus cheapest of all cars.
  If P is cheaper then A then R must be cheapest of all cars and bikes.
• 9 years agoHelpfull: Yes(0) No(0)