A can hit the target 3 times in 6 shots, B 2 times in 6 shots & C 4 times in 6 shots. They fire a volley. Whats the probability that at least 2 shots hit?
Options
1/2
1/3
2/3
1/4
3/4

• 1/2
  
  Probability of A=1/2, B=1/3, C=2/3
  Probability of hitting at least 2 shots=(A & B hits & not C) OR (B & C hits & not A) OR (A & C hits & not B) OR (all A, B & C hits)
  =(1/2)(1/3)(1/3)+(1/3)(2/3)(1/2)+(1/2)(2/3)(2/3)+(1/2)(1/3)(2/3)
  =9/18= 1/2
• 10 years agoHelpfull: Yes(0) No(0)
• Ans.-1/2
  probability of hitting the target at least once=p(A hits&B hits&C hits)or p(A hits & B hits & C does not hits) or p(A and C hits but B does not hit) or p(B&C hits and A does not hit)
  =(3/6)*(2/6)*(4/6)+(3/6)*(2/6)*(2/6)+(3/6)*(4/6)*(4/6)+(3/6)*(2/6)*(4/6)
  =1/2
• 10 years agoHelpfull: Yes(0) No(0)