A girl start to count on the fingers of her left hand. as thumb on 1, index finger on 2, middle finger on 3,ring finger on 4, little finger on 5 then reversed back ring finger on 6,middle finger on 7,index finger on 8 ,thumb on 9, and 10 on index finger and so
on...she counted upto 1994 .on which she end the count

• middle finger..... on 1st count 1 comes on thumb followed by 9 in the second count and 17 in the third count.... it forms an AP with a common difference of 8... 1,9,17,25 and so on... if we solve it
  a+(n-1)d=1994
  then n-1=1994/8
  which will give as a remainder.... so 1992 will be counted on thum and then 1993 on index finger and 1994 on middle finger
• 10 years agoHelpfull: Yes(4) No(1)
• middle one.
  
• 10 years agoHelpfull: Yes(1) No(0)
• Index finger;
  bcoz the pattern is thumb=8*n+1; index =8*n or 8*n+2;
  middle=8*n-1 or 8*n+3; ring=8*n+4 or 8*n-2; little=8*n+5 or 8*n-3;
• 10 years agoHelpfull: Yes(1) No(1)
• sorry its index finger not the middle one since 1993 will be counted on thumb... so index finger will be 1994
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• ans
  ring finger
• 10 years agoHelpfull: Yes(1) No(0)