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what are the last two digits of expression 5306^214
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- for 5306^214
the last digit will always determined by the expansion of 6^214
hence, 6^214=6^200*6^14
=(6^2)^100*(6^2)^6*6^2
=>>6*6*36
as the expansion of (6^2) must consist 36
so last 2 digit =>>96(answer)
- 10 years agoHelpfull: Yes(8) No(1)
- last two digit is 96...
because cyclic factor of 6=1 that's why last digit =1
and (5306*5306) last two digit is 36 and the power become 107...
after 5 time multiplication we will get again 36..
so 107/5 reminder=2
36*6=216{we multiply by6 because in5306 second last digit is 0.it has no effect}
16*6=96...this is the asn...
- 10 years agoHelpfull: Yes(4) No(0)
- easy method as unit digit is 6,,,214/6 we get rem as 4 so (6^4)=1296 the last two digit is 96.
- 10 years agoHelpfull: Yes(4) No(0)
- Answer is 06.
Cyclic factor of 6 = 1 thats y last digitt =1.
to fond the 10th's digit we have to multiply the 10th's digit from 5306 and the unit's digit from 214 which is 0. therfore 06 is the answer. - 10 years agoHelpfull: Yes(1) No(0)
- 5306*5306=last two digit 36.after multiplication of five times it again 36.then 5036^210 last two digit 36.after rest 4 times it is 56.then 56 is answer
- 10 years agoHelpfull: Yes(0) No(6)
- when ever we have something as 6^x we will always get 6 as the last digit
- 10 years agoHelpfull: Yes(0) No(2)
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