HCL
Company
. A digital wristwatch was set accurately at 8.30 a.m and then lost 2 seconds every 5 minutes. What time was
indicated on the watch at 6.30 p.m of the same day if the watch operated continuously that time ?
(A)5:56 B)5:58 (C)6.00 (D)6.23 (E)6.26
Read Solution (Total 4)
-
- E)6.26
for every 5min watch looses 2secs, so for 60ms it looses 24 sec,
ie., fo 1hr it looses 24 secs
8.30amto6.30pm=10hr it looses 240secs ie., 4mins , hence d watch wil show 6.26 - 13 years agoHelpfull: Yes(33) No(0)
- (E)6.26
8.30 a.m. to 6.30 p.m. takes 10 hr.
In 5 min watch loses 2 sec
1 min loses 2/5 sec
60 min loses=(2/5)*60 sec
10*60 min loses=(2/5)*60*10 sec
10 hr loses=240 sec i.e.4 min loses
so,6.26 - 13 years agoHelpfull: Yes(10) No(0)
- Minutes b/w 8.30 am & 6.30pm = 10hours=600mins
From given: If 5min=loss of 2seconds then 600mins = 240seconds..(i.e) 4 minutes
Therefore 4 minutes is subtracted from 6.30 pm we get 6:26 pm
Ans : 6.26 pm - 10 years agoHelpfull: Yes(0) No(0)
- Watch was set at 8.30 am.
For each 5 mins, it loses 2 secs.
Then for 1 hr , there is (60/5)=12 (5)mins.
But it loses 12*2=24 secs for 1 hr
Time between 8.30 am to 6.30 pm is 10 hr . The lose of time is 10*24=240 seconds. i.e 4 mins lose
6.30-0.04=6.26pm
Ans:- (E) 6.26 - 3 years agoHelpfull: Yes(0) No(0)
HCL Other Question