Afcat exam
Exam
Numerical Ability
Age Problem
Three years ago the average age of A & B was 18 years. With C joining them now, the average age becomes 22 years. How old is she?
Read Solution (Total 4)
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- u mean to say C?
present average age of A and B =18+3=21
so c's present age=22+(22-21)*2=24 years - 10 years agoHelpfull: Yes(2) No(0)
- let age of A be = x years
age of B = y years
Three years ago A = x-3 years
similarly three years ago B = y-3
avg age of A+B/2= (x-3+y-3)/2 = 18 ==> x+y = 42 years
After joining of C avg of A,B,C = (A+B+C)/3 = (42+C) =22*3==? C=24 YEARS OLD
- 10 years agoHelpfull: Yes(1) No(0)
- present age of A & B is =(18*2)+6=42;
after joining of c,
present age of A,B & C is=22*3=66;
so age of C is=66-42=24. - 10 years agoHelpfull: Yes(1) No(0)
- (A-3)+(B-3)/2=18
A+B=30-----(1)
NOW
A+B+C/32=22
30+C=66 [FROM (1)]
C=36(ANS)
- 10 years agoHelpfull: Yes(0) No(2)
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