Ram and Shakil run a race of 2000 meters. First, Ram gives Shakil a start of 200 meters and beats him by one minute. If , Ram gives Shakil a start of 6 minutes Ram is beaten by 1000 meters. Find the time in minutes in which Ram and Shakil can run the races separately.

• Let x and y are the speeds of Ram and Shakil.. Then by problem we got following equation
  2000/x=(1800/y)-1
  1000/X=(2000/y)-6
  solve equation 1 and 2, we get x=250 and y=200
  Therefore, Time taken by Ram and Shakilk to complete a race of 2000m is 8 min and 10 Min
  
• 9 years agoHelpfull: Yes(90) No(7)
• LET r be velocity of ram and s be the velocity of Shakil
  then
  (2000/r)=(1800/s)-60......(1)
  second case
  distance Shakil travel in 6 min=360s
  again equating time for both
  1000/r=(2000-360s)/s.......(2)
  solving (1) &(2) we get s=20/6
  putting value in first we get time =480sec=8min
  
• 9 years agoHelpfull: Yes(71) No(28)
• Since A/Q Ram Travel : 2000m
  sakil travel: 1800 =1800-velocity
  According To Question= 2000/1000=1800-v/2000-6v (eq 1 )
  velocity =200m/min
  time taken by sakil =2000/200=10min
  Since ram time taken =8min
  This is Final Answer
• 9 years agoHelpfull: Yes(24) No(12)
• state ment 1 :
  ram ran 2000m
  shakil ran 2000-200=1800m
  
  ram takes x sec to run 200 m and shakil takes 'x+60' sec to run 1800m so time taken to run 1m
  ram--- x/2000
  shakil--- (x+60)/1800
  
  
  statement 2 :
  ram gave 6 mint i.e. 3600 sec lead and got beaten by 1000m
  so ram ran 1000m
  shakil ran 2000m
  
  ram takes y sec to run 1000m where shakil takes 'y+3600' sec to run 2000 , so time taken to run 1m
  by ram -- y/1000
  by shakil -- (y+3600)/2000
  
  
  now solving
  
  x/2000=y/1000 & x+60/1800 = y+3600/2000
  we get x=8m and y= 10m
• 8 years agoHelpfull: Yes(13) No(4)
• from where does (1800/s)-60 came? plz elaborate the steps
• 9 years agoHelpfull: Yes(5) No(11)
• ram runs the race in 12 min
  and shakil in 18
• 9 years agoHelpfull: Yes(1) No(13)
• ram travel 2000m then sakil travel 1800-v.[v=velocity of sakil]
  ram travel 1000m then sakil travel 2000-6v.
  i.e.2000/1000=1800-v/2000-6v
  v=200m/min
  time taken by sakil=2000/200=10min
  similrly time taken by ram=8min
  
• 8 years agoHelpfull: Yes(1) No(1)
• that 60 cums from one minute represented in question NANDITA
  
• 9 years agoHelpfull: Yes(0) No(6)
• i can't understand the question.what does gives a start a start means? plz some one explain
  
• 7 years agoHelpfull: Yes(0) No(0)
• LET r be velocity of ram and s be the velocity of Shakil
  then (2000/r)=(1800/s)-60---(1)
  second case---distance Shakil travel in 6 min=360s
  again equating time for both
  1000/r=(2000-360s)/s--(2)
  solving (1) &(2) we get s=20/6
  putting value in first we get time =480sec=8min
• 3 years agoHelpfull: Yes(0) No(0)