Two vertical poles 2 meters and 8 meters high stand apart on a horizontal plane. The height in meters of the point of intersection of the lines joining the top of each pole to the bottom of the pole is.

a. 5.6
b. 1.8
c. 1.6
d. cannot be determined.

• first of all draw the diagram correctly..the condition says that the point of intersection of the lines joining the top of each pole to the bottom of the pole...now draw the diagram..
  step 1:draw pole AB of 2m horizontally and den draw pole CD of 8m at some dist apart from foot of AB
  
  step 2: now join the foot of both the towers.
  
  step 3: now join AD and BC,and name the point of intersection of these lines as .
  
  step:4 now draw a perpendicular from E to line BD.and name that point F and say EF=x
  
  step:5 now F divides both BD in two parts let it be P and Qi.e BF =p and FD = Q.
  
  step:6 now observe triangle ABD& EFD,they are similar hence x/Q=2/P+Q
  x= 2Q/P+Q......(1)
  
  step:7 now observe triangle CBD and EBF,they are also similar hence x/P=8/P+Q
  x=8P/P+Q......(2)
  
  step:8 now equate (1) and (2)
  we will get Q=4P now put Q=4p in equation (1)
  i.e x/4P=2/5p
  x= 8P/5P
  x=1.6-(answer)
  
  hope its helpful to you
• 10 years agoHelpfull: Yes(253) No(5)
• we have a formula p*q/(p+q)
  so ans is 2*8/2+8= 16/10=1.6
• 10 years agoHelpfull: Yes(68) No(0)
• NANDITA i love you
• 10 years agoHelpfull: Yes(53) No(34)
• Ans-1.6m.
  Let intersection pt is x.
  
  base=a=a1+a2;tana1=8/a=x/a1;tana2=2/a=x/a2;
  a=(x/tana1)+(x/tana2);a=xa/8+xa/2,
  1=5x/8,
  x=8/5=1.6m
  
• 10 years agoHelpfull: Yes(19) No(4)
• let x is height of intersection.m & p is distance from 8m pole and 2m pole to intersection pt respectively.
  From the property of similar triangles,
  we equate the sides of the triangles
  i.e.
  8/x = (p+m)/p
  and
  2/x = p+m/m
  Now let us reverse the 2 equations as:-
  x/8 = p/(p+m)
  and
  x/2 = m/(p+m)
  Now adding we get,
  x/8 + x/2 = (p+m)/(p+m) = 1
  Thus solving we get x = 1.6
• 10 years agoHelpfull: Yes(12) No(1)
• let x is height of intersection.m & p is distance from 8m pole and 2m pole to intersection pt respectively.
  From the property of similar triangles,
  we equate the sides of the triangles
  i.e.
  8/x = (p+m)/p
  and
  2/x = p+m/m
  Now let us reverse the 2 equations as:-
  x/8 = p/(p+m)
  and
  x/2 = m/(p+m)
  Now adding we get,
  x/8 + x/2 = (p+m)/(p+m) = 1
  Thus solving we get x = 1.6
• 9 years agoHelpfull: Yes(3) No(0)
• p*q/p+q=1.6
  
• 9 years agoHelpfull: Yes(3) No(2)
• can't determine, because horizontal length is not given
• 10 years agoHelpfull: Yes(2) No(8)
• can not be determined
• 10 years agoHelpfull: Yes(2) No(7)
• 1/2 + 1/8 = 1/x
  x = 8/5 = 1.6
  
• 9 years agoHelpfull: Yes(2) No(0)
• thank you nandita for elaborating the problem and thank you rahul for giving such a short and quick formula.
• 10 years agoHelpfull: Yes(1) No(0)
• c . 1.6 apply pytogoras theorem eguate the base for each traingle
• 10 years agoHelpfull: Yes(0) No(0)
• @AJAY KUMAR RAI
  can you pls elaborate
• 10 years agoHelpfull: Yes(0) No(0)
• plz explain the ans briefly
• 10 years agoHelpfull: Yes(0) No(1)
• let x is height of intersection.m & p is distance from 8m pole and 10m pole to intersection pt respectively.
  from 8/x=(p+m)/m -(1)
  10/x=(p+m)/p -(2)
  add p+m frm equ 1 &2
  1/x=(1/8+1/10)=>x=4.44
• 10 years agoHelpfull: Yes(0) No(7)
• can anyonne plz pst the corct ans
• 10 years agoHelpfull: Yes(0) No(1)
• d.cannot be determined
• 10 years agoHelpfull: Yes(0) No(7)
• NANDITA SHRIVASTAVA has explained perfectly... good job..
• 10 years agoHelpfull: Yes(0) No(5)
• answer should come between 2 and 8 nandita
• 10 years agoHelpfull: Yes(0) No(0)
• correct ans is 1.6 i attend tcs openseasame
• 9 years agoHelpfull: Yes(0) No(2)
• height= (8+2)/8*2=1.6
• 9 years agoHelpfull: Yes(0) No(5)
• hello kautilya
• 7 years agoHelpfull: Yes(0) No(0)