Roy is now 4 years older than Erik and 2 years older than Iris. If in 2 years, Roy will be twice as
old as Erik, then in 2 years what would be Roy's age multiplied by Iris's age?
a)48
b)28
c)50
d)52

• ans is option a)48
  roy=r
  eric=r-4
  iris=r-2
  r+2=2(r-2)
  r=6
  iris age is
  6-2=4
  after 2 years
  iris age=6
  roy age=8
  multiply 6*8=48
• 9 years agoHelpfull: Yes(27) No(2)
• Let Erik's age= X
  roy=X+4, Iris=X+2
  in 2 years Erik=X+2
  Roy=X+6 and accoring to the question X+6=2*(x+2)
  X=2
  now 8*6=48
• 9 years agoHelpfull: Yes(7) No(1)
• let us assume roy age= x
  then according to question, roy is 4 year older than erik.. means erik is 4 year younger than roy
  so erik age= roy age-4=
  r-4
  in the same fashion iris age= r-2
  after 2 year roy age= r+2
  and erik= (r-4)+2=r-2
  so according to given condition
  r+2=2(r-2) .........after solving
  so r=6
  iris=6-2=4
  but after 2 year 4+2=6
  and roy after 2 year 6+2=8
  multiplication gives= 6*8=====48
• 9 years agoHelpfull: Yes(2) No(0)
• 48
  present age of roy=E+4=I+2
  after 2 years, 2(E+2)=E+6
  present age E=2, R=6, I=4
• 9 years agoHelpfull: Yes(1) No(0)
• a)48 is correct.
  suppose Erik's age is x &Iris's age (x+2)&Roy's age is (x+4)
  x+4+2=2(x+2)
  or.x=2
  so,after 2 yr R=8 yr & I=6 yr.
  so, ans is(6*8)=48.
• 9 years agoHelpfull: Yes(1) No(0)
• 48.
  
  6*8=48
• 9 years agoHelpfull: Yes(1) No(0)
• x,x+2,x+4
  2 years after roy=x+6, erik=x+2
  roy will be twice as old as erik=> x+6=2(x+2)=>x=2
  roy=2+6=8
  erik=2+4=6
  product=6*8=48
• 9 years agoHelpfull: Yes(1) No(0)
• roy=erik+4 and
  roy=iris+2,and in 2 years roy=2*erik
  therfore,
  2*erik=erik+4===>erik=4
  roy=8 and iris=6
  therefore the ans is 48
• 9 years agoHelpfull: Yes(1) No(0)
• let roy erik iris
  x+4 x x+2 ............(1)
  then in 2 years roy will be double of erik so,
  now it becomes,
  x+6=2(x+2)
  x=2
  substitute x valuue in eq1
  roy =6
  erik=2
  iris=4
  2 years hence roy=8
  erik=4
  iris=6
  now 6*8=48
  option(a) is correct
• 9 years agoHelpfull: Yes(0) No(0)
• R=4+E-----(1)
  R=2+I-----(3)
  R+2=2(E+2)
  SO, R=2E+2-----(2)
  EQUATE 1 AND 2
  2E+2=4+E
  SUB IN 1 AND 3
  E=2
  IMPLIES R=6 I=4
  AFTER 2 YEARS
  R=8 AND I=6;
  SOLUTION 8*6=48
  
• 9 years agoHelpfull: Yes(0) No(0)
• let r be roy, e be erik, i be iris
  r=e+4
  r=2+i
  r+2=2(e+2)
  2+4+e=2e+4
  e+6=2e+4
  e=2
  r=6
  i=4
  (r+2)*(i+2)=8*6=48
• 9 years agoHelpfull: Yes(0) No(1)
• 48 is the answer.
  Roy=Erik+4.......(1)
  Roy=Iris+2........(2)
  Roy+2=2(Erik+2)....(3)
  
  
  now solving equations (1),(2),(3)
  we get
  Roy=6
  Erik=2
  Iris=4
  Now two years later
  Roy will be 8 and Iris will be 6
  So multiplying 8 * 6=48
  
  
• 9 years agoHelpfull: Yes(0) No(0)