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Numerical Ability
Simple & Compound Interest
A man borrows Rs. 1200.00 from a bank for a period of 3 months. He finds that he has to repay Rs.
1236.00. The bank rate of interest is:
(A) 3% (B) 6%
(C) 12% (D) 24%
Read Solution (Total 5)
-
- options s (C)
amount returnd s 1236 , so interst Rs.36, borrowd 1200, n=3/12, so 36=(1200*3*r)/12*100, thus r=12% - 13 years agoHelpfull: Yes(18) No(1)
- c)12%
S.I=1236-1200=36
time=3/12 year
S.I.=P*R*T/100
36=(1200*R*3)/12*100
R=12% - 12 years agoHelpfull: Yes(12) No(0)
- IN THIS QUESTION SIMPLE INTEREST IS RS 36 ---- FROM(1236-1200)
TIME IS 3MONTHS SO WE CAN SAY IN YEARS ITS 1/4 OF A YEAR ---- FROM(12MONTHS/4=3MONTHS)
SO SIMPLY APPLYING SIMPLE INTEREST FORMULA
SI=P*R*T/100
36=1200*R*1/400
WE GET R=12% PER YEAR SO THE ANSWER IS OPTION C. - 12 years agoHelpfull: Yes(1) No(0)
- r=si*100/p*t
=36*100/1200*3
12% - 12 years agoHelpfull: Yes(0) No(1)
- c)12%
S.I=1236.00-1200.00=36.00
P=1200.00
T=3 months=3/12 year
R=?
S.I=P*T*R/100
36=1200*3*R/(12*100)
R=36*12*100/1200*3
R=12 - 4 years agoHelpfull: Yes(0) No(0)
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