XYY XZ ABCX XYY-XZ DYX find the digit D

How are you getting xyy = 955 and xz = 96 please explain!
9 years agoHelpfull: Yes(1) No(0)
XYY+XZ=ABCX,If u take XYY=955 and XZ=96 then the sum is 1051(ABCX),where X is not equal to 9,then how you assumed XYY to be 955?
9 years agoHelpfull: Yes(1) No(0)
XYY = 955 and XZ = 96
XYY - XZ = 955-96 = 879
So D = 8
9 years agoHelpfull: Yes(0) No(2)
XYY = 955 and XZ = 96
XYY - XZ = 955-96 = 859
So D = 8
9 years agoHelpfull: Yes(0) No(1)
XYY
+ XZ
_____
ABCX

Here it is observed that 3 digit + 2 digit = 4 digit. In such a situation the value of A is always 1 because the values of other letters will lie between 0 and 9 and max is 9. As a result, we can also conclude that X=9 and so B=0. So we can write

9YY
+ 9Z
_____
10C9

Now Y+Z=9 and Y+9 = 10+C since there is carry on X in 3 digit. So Y=1+C. Possible combination of Y,Z : (2,7), (3,6), (4,5) and NOT (1,8) since A=1.

Now C should be less than equal to 8.

9YY
- 9Z
_____
DY9

Here Y-Z=9. So Y
7 years agoHelpfull: Yes(0) No(0)

XYY+XZ=ABCX
XYY-XZ=DYX
find the digit D