Self
Maths Puzzle
Numerical Ability
Number System
what is the remainder when 15^2010 +16^2011 is divided by 7
Read Solution (Total 3)
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- Ans is 3
15^2010/7=1^2010/7
remainder is 1
now
16^2011/7=2^(4*2011)/7=((2^3)^(8044/3))/7=(8^2681)2/7=(1^2681)2/7
=2/7=remainder 2
total remainder=1+2/7=3/7=3 - 10 years agoHelpfull: Yes(6) No(1)
- The last digit of 15^2010 is 5 and for 16^2011 is 6.
Thus, (5+6)/7 = 11/7 i.e remainder=4 - 10 years agoHelpfull: Yes(1) No(4)
- ANS is:4
15*15 UNIT DIGIT IS 5
15*15*15 UNIT DIGIT IS 5
SO 15^2010 UNIT DIGIT IS 5...
16*16 UNIT DIGIT IS 6
16*16*16 UNIT DIGIT IS 6
SO 16^2011 UNIT DIGIT IS 6...
5+6=11
11/7=11-7=4 Remainder
- 10 years agoHelpfull: Yes(1) No(6)
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