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A class of 100 students. 24 of them are girls and 32 are not. Which base am I using?
Read Solution (Total 7)
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- if base be b then
100 = 24 + 32
=> 1*b^2 + 0*b^1 + 0 = (2b+4) + (3b+2)
=> b^2 - 5b -6 = 0
=> (b-6)*(b+1) = 0
=> b = -1,6
base can't negative
so, b = 6 - 10 years agoHelpfull: Yes(21) No(1)
- 24+32=100
4+2=6
6-0=6
s0 base 6
- 10 years agoHelpfull: Yes(3) No(0)
- (2b+4) + (3b+2) = 1b^2 + 0b + 0 ( b is the base)
calculating we get
b^2 - 5b - 6 = 0
so we get 6 as soln - 10 years agoHelpfull: Yes(2) No(0)
- base use is 6
- 10 years agoHelpfull: Yes(0) No(1)
- Base is 6.
100base6=24base6 + 32 base 6
36=16+20.. - 10 years agoHelpfull: Yes(0) No(0)
- Let the base be X.
Therefore
(X*X + X*0 + 0) = (2*X +4) + (3*X + 2)
X*X = 5*X + 6
X*X - 5*X -6 = 0
(X-6)(X+1) = 0
Therefore base is 6 - 9 years agoHelpfull: Yes(0) No(0)
- ratio and proportion
- 8 years agoHelpfull: Yes(0) No(2)
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