a 3 digit number is divided successively in order by 4,5,6 leaving remainders 2,3,4. how many such numbers are possible?.
answer given -7

• ans: 15
  
  4-2 =5-3 = 6-4 = 2
  
  lcm(4,5,6)= 60
  number will be (60k -2)
  as no. is of 3-digit , k = 2,3,4,5,6,..., 15,16
  15 numbers possible
• 9 years agoHelpfull: Yes(13) No(0)
• 4(5(6k+4)+3)+2
  that becomes 120k+94
  now go on putting values from 1,2,3,....
  for k=7,value =934(three digit)
  for k=8,value=1054(not three digit)
  so 7 values and hence 7 nos. possible
  
• 9 years agoHelpfull: Yes(8) No(2)
• please someone provide the solution
• 9 years agoHelpfull: Yes(0) No(0)