sum of fibonacci numbers1,6,7,13,20.... upto 52 terms?

• Observing the sequence 1, 6, 7, 13, 20 and so on,
  It can be re-written as 1, (1+5), (2+5), (3+10), (5+15), (8+25), and so on.
  
  The sequence thus decomposes into sum of two standard Fibonacci sequences,
  1, 1, 2, 3, 5, 8, 13 up to 52 terms and 5*(1, 1, 2, 3, 5, 8, 13 up to 51 terms).
  
  So the sum is given as : Sum of 52 terms of the standard Fibonacci series + 5*Sum of 51 terms of the standard Fibonacci series. Which is equivalent to 6*Sum of 51 terms in the standard Fibonacci series + the 52th term. And since sum of n terms of a fibonacci series is given as F(n+2)-1,
  
  The sum should be 6*{F(53)-1}+F(52) = F(52) + 6*F(53) - 6.
• 9 years agoHelpfull: Yes(3) No(0)
• SUM OF N TERMS OF FIBBONICA SERIES WILL BE(n+2-1)FIBONNICA NUMBER
  EG:
  LET FS BE:
  1 6 7
  SUM OF IST TWO NUMBERS WILL BE THE THIRD NUMBER ACCORDING TO THE FORMULA
  SO HENCE 7
• 9 years agoHelpfull: Yes(2) No(26)
• What is the corrct Ans??
• 9 years agoHelpfull: Yes(0) No(0)
• kindly post the right formula..
• 9 years agoHelpfull: Yes(0) No(0)