. No when divided by 5, 2, 3 successively in order to get remainder 0, 1, 2.what is remainder
of same no when divided by 2, 3, 5 successively?

• 5|X
  2|y - 0
  3|z - 1
  |1 - 2
  from here we get, z= 3*1+2=5
  y= 2z+1 = 2*5+1=11 and x= 5y+0 = 55
  so the number is 55....when it will be divided by 2,3 and 5 the remainders will be 1,0,4 respectively
• 9 years agoHelpfull: Yes(45) No(16)
• 3+2 = 5, 5*2 + 1 = 11, 11*5 = 55
  
  smallest no. is 55
  when 55 is divided by 2,3,5 we get rem as 1,1,0
• 9 years agoHelpfull: Yes(23) No(45)
• number which successively divided by 5,2,3 and give reminder 0,1,2 is 175
  and when the same no divided by 2,3 and 5 it gives reminder 1,0,4
• 9 years agoHelpfull: Yes(22) No(11)
• 5 2 3
  
  0 1 2
  now,
  2*2+1=5
  5*5+0=25
  Now,
  25/2=qutoint=12 and remainder=1
  12/3= qutoint= 4 and remainder=0
  4/5 = qutoint=0 and remainder= 4
  hence answer is 1 0 4
  
• 9 years agoHelpfull: Yes(13) No(2)
• ans will be 1,2,0.....
  like if we take 35 n then apply given condition
  
• 9 years agoHelpfull: Yes(12) No(6)
• Let x is the number
  x= 5*k+0 (k is qutoint)
  k=2*L+1 (L is qutoint)
  L=3*M+2 (M is qutoint)
  => K= 2*(3*M+2)+1 = 6M+5
  => x= 5*( 6M+5)+0
  => x =30*M+25;
  Put M=1, x=55; M=2, x=85;...so on
  let no. is 55 Then,
  55/2 = rem= 1 and qusnt=27; 27/3= rem=0 and qusnt=9; 9/5= rem=4 qusnt=1
  rem after successively divide by 2, 3, 5 is 1, 0, 4
• 8 years agoHelpfull: Yes(12) No(0)
• As the question info is inadequate
  I am taking the number as 5,
  when 5 is divided by 5,2,3 it will give a remainder of o,1,2 respectively.
  Again when 5 is divided by 2,3,5 it gives a remainder of 1,2,0.
  
• 9 years agoHelpfull: Yes(7) No(1)
• 85 is the number
  85/5 gives 17 as questient and rem=0
  now divide 17/2 gives q=8 and rem=1
  now divide 8/3 gives r=2
  now divide 85 successively by 2,3,5 and u will get rem 1,0,4
  
• 9 years agoHelpfull: Yes(5) No(0)
• First read the the question carefully.
  follow these steps properly:
  
  get started------
  (According to the Divisibility rule DIVIDEND=DIVISOR*QUOTIENT+REMAINDER)
  
  5(2(3k+2)+1)+0
  5(6k+4)+1)+0
  5(6k+5)+0
  Now the number is 30k+25
  according to the ques. we're dividing this no consecutively by 2,3,and 5 as below
  
  (30k+25)/2= 15k+12 here when we divide 30k by 2 we'll get 0 as remainder but when we'll divide 25 by 2 we'll get 1 as remainder. OK, now next step we consider 15k+12 as the number instead of taking 30k+25.
  now,
  
  (15k+12)/3= 5k+4 as we discussed above the we'll get the remainder as 0.
  Again, we're taking the no.
  
  (5k+4)/5= k and 4 isn't divisible by 5 so it's considered as Remainder.
  
  so finally we got the remainder is 1,0,4.
• 8 years agoHelpfull: Yes(4) No(0)
• suppose quotient is K
  we can say that from the given
  5(2(3K+2)+1 -> 30K + 25 (dividend)
  now divide successively 2,3 and 5 with the dividend.
  we get 1, 0, 4 as remainder
  
• 9 years agoHelpfull: Yes(2) No(1)
• the number is 5 which gives remainder 0,1,2
  nd the same number when divided by 2,3,5 remainder will come=1,2,0 ANS
• 9 years agoHelpfull: Yes(2) No(2)
• answer is 1 2 0
  Solution:- let us consider the number be 5. So according to calculation we get remainder as 1 2 0 when 5 is divided by 2,3,5.
• 9 years agoHelpfull: Yes(1) No(0)
• 145 can be the no. as when divided by 5 r=0 ==> 29 by 2 r=1 ==>14 by 3 r=2
  so when 145 is divided by 2 r=1 ==> 72 by 3 r=0 ==> 24 by 5 r=4
  i.e
  1,0,4 is the ans
• 8 years agoHelpfull: Yes(1) No(0)
• This can be solvd through options easily...
• 8 years agoHelpfull: Yes(1) No(0)
• Answer is 1,2,0
  if we consider the no is 5 then we get the remainder
  
  5/5=R(0) , 5/2= R(1) , 5/3= R(2)
  so
  5/2= R(1), 5/3=R(2) , 5/5=R(0)
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• that no can be.....35...65...95...and so on...because when divided by 5 it gives remainder 0.....so it is 5m type no....so remainder are....1...,,,2,,,and something for third no...
• 9 years agoHelpfull: Yes(0) No(0)
• let N be the number;
  N=5*k;
  k=2*t+1;
  t=3*p+2;
  
  p t k N
  1 5 11 55
  2 8 17 85
  
  similarly we have more option.but
  now try by taking N=55
  55%5=0;
  11%2=1
  5%3=2;
  
  so condition satisfied
  now
  55%2=1;
  27%3=0;
  9%5=4
• 9 years agoHelpfull: Yes(0) No(1)
• the remainder will be 1 in each case because that no. is obviously an odd no. then only you can get 0 remainder on dividing by 5 and 1 remainder on successively dividing by 2.
  So a no. which is odd on dividing by 2 will give remainder 1 and after that if you will divide 1 by any natural no. (except 1 itself) you will get 1 as remainder.
• 9 years agoHelpfull: Yes(0) No(0)
• remainder will be 1,0,5
• 9 years agoHelpfull: Yes(0) No(0)
• 1,2,0 is ans as the no is 5
• 8 years agoHelpfull: Yes(0) No(0)
• no is 65
  and remainders are 1 2 0
• 8 years agoHelpfull: Yes(0) No(0)
• the no. is 30t+25 let t=(1,2,3........infinity)
• 7 years agoHelpfull: Yes(0) No(0)