The price of a commodity (in rupees per kilogram) is 100+0.1n on the nth day of 2007 (n=1,2,....100), and then remains constant. On the other hand, the price of another commodity ( in rupees per kilogram) is 89+0.15n, on the nth day of 2007 (n= 1,2,...365). On which date in 2007, will the prices of these two commodities be equal?

may 21
april 11
april 10
may 20

• For the first commodity, At the end of 100th day,
  the price is C1=100+0.1*100= 110, after 100th day price remains same.
  
  For 2nd commodity,
  
  At the end of 100th day, C2=89+0.15*100 = 104
  (for every 10 days, C2 get increased by 1.5 (i.e 10*0.15) So,)
  at 110th day, C2=104+1.5=105.5
  at 120th day, C2=105.5+1.5=107
  at 130th day, C2=107+1.5=108.5
  at 140th day, C2=108.5+1.5=110
  
  So, C1 and C2 are equal at 140th day.
  140th day in 2007 is May-20
  
  
  
• 10 years agoHelpfull: Yes(32) No(1)
• may 20 i.e., on 140th days
  on 140th day, price of frst commodity iz 110(100+0.1*100) and another commodity price is 89+0.15(140)=110;
  
• 10 years agoHelpfull: Yes(27) No(7)
• the price of a commodity remains constant after the 100th day (n=100).
  If the prices of the two commodities become equal before n = 100, then
  100 + 0.1n = 89 + 0.15n
  . n = 220, which is not possible. (Since n has been assumed to be less than 100)
  . The prices of the two will be equal after n = 100,
  i.e., when the price of one = 100 + 0.1 × 100 = 110
  . 89 + 0.15n = 110
  . n = 140
  2007 is not a leap year. Number of days till 30th April = 31 + 28 + 31 + 30 = 120
  The prices of the two will be equal on 20th May.
  
• 9 years agoHelpfull: Yes(10) No(0)
• I think all the options are wrong.
  
  on may 21:
  C1 ==> 114.1
  C2 ==> 110.15
  
  on april 11:
  C1 ==> 110.1
  C2 ==> 104.15
  
  on april 10:
  C1 ==> 100
  C2 ==> 104
  
  on may 20:
  C1 ==> 114
  C2 ==> 110
  
  
  
  
  
• 10 years agoHelpfull: Yes(4) No(14)
• may 20.
  for n=140 both will equal.
  as first commodity maximum price will be 110 for n=100 beyond 1oo it will remain constant.
  
• 10 years agoHelpfull: Yes(4) No(2)
• may 20.
  for n=140 both will equal.
  as first commodity maximum price will be 110 for n=100 beyond this no it will remain constant.
• 10 years agoHelpfull: Yes(3) No(0)
• i think on 22oth day.
  as 100+0.1n=89+0.15n
  n=220
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(2) No(11)
• 100+0.1 * (31+28+31+10)=89+.15 *(31+28+31+10)=110
  so its april 10
• 10 years agoHelpfull: Yes(1) No(5)
• Answer is MAY 20 because after 100 days price of first will remain constant sothey can be equal after that only you can also take that assumption by looking to optionso equation will be11089320nn140thus 20 MAY
• 10 years agoHelpfull: Yes(1) No(1)
• Since, At the end of 100th day for the first commodity,
  the price is C1=100+0.1*100
  = 110,
  
  after 100th day price remains same.
  For 2nd commodity,
  
  At the end of 100th day,
  C2=89+0.15*100
  = 104
  (for every 10 days, C2 get increased by 1.5 (i.e 10*0.15) So,)
  
  at 110th day,
  C2=104+1.5
  =105.5
  at 120th day,
  C2=105.5+1.5
  =107
  at 130th day,
  C2=107+1.5
  =108.5
  at 140th day,
  C2=108.5+1.5
  =110
  So, C1 and C2 are equal at 140th day.
  140th day in 2007 is May-20
  
• 9 years agoHelpfull: Yes(1) No(0)
• april 10
  100 days = 31+28+31+10
• 10 years agoHelpfull: Yes(0) No(4)
• @niharika : plz explain it properly
• 10 years agoHelpfull: Yes(0) No(2)