A year ago Mohit was four time his son s age In six years his age will be 9 more

Ans = 9 years

present age of son= x
a year ago mohit age= 4(x-1)
so present age of mohit=4(x-1)+1

after 6 year

4(x-1)+1+6-9=2(x+6)
4x-4+7-9=2x+12
2x=18
x=9
10 years agoHelpfull: Yes(28) No(0)

9 years

If present age of Mohit=M & Son=S, then
M-1= 4(S-1), M-4S=-3 ---(i) &
M+6=9+ 2(S+6), M-2S=15 ---(ii)
On Solving (i) & (ii), M=33, S=9
10 years agoHelpfull: Yes(12) No(3)
let the age of son is x yr and father is y yr.
1s eq...
4(x-1) = y-1 => 4x-y = 3
from here y = 4x+3

2nd eq....
2(x+6)+9 = y+6
2x+12+9 = y+6
2x-y = -15

taking value of y...
2x-4x-3 = -15
-x = -12
x = 12 ans
10 years agoHelpfull: Yes(4) No(6)
ANSWER==> 9 years
let present age of Mohit= X and son= Y
then x-1=4(y-1)
and x+6=2*(y+6)+9
soling this we get Y= 9
10 years agoHelpfull: Yes(2) No(0)
let mohit age be x and that of his son be y.
x-1= 4(y-1);
x+6=2(y+6)+9;
4y-2y+3=21;
since ,y=18/2=9ans.
10 years agoHelpfull: Yes(1) No(0)
ans will be 9
son age one year ago=x
mohit age =4x
after 6 year
son age=x+7
mohit age= 9+2(x+7)
hence
4x+7=9+2(x+7)
will get x=8
so the present age of son will be: x+1=8+1=9;
10 years agoHelpfull: Yes(1) No(0)
present age of son = x years.

a year ago,
mohit age = 4(x-1)
present age of mohit = 4(x-1)+1

in six years,
4(x-1)+1 +6 = 9+2(x+6)
4x+3=2x+21
2x=18
x=9

son age is 9 years.
10 years agoHelpfull: Yes(1) No(0)
present age of son= x
a year ago mohit age= 4(x-1)
now age of mohit= 4(x-1)+1
a/q

after 6 year
4(x-1)+1+6-9=2(x+6)
4x-4+7-9=2x+12
2x=18
x=9
10 years agoHelpfull: Yes(1) No(0)
srry its

2x = 12
x = 6.
10 years agoHelpfull: Yes(0) No(9)
17/2 years
10 years agoHelpfull: Yes(0) No(2)
17/2 years
10 years agoHelpfull: Yes(0) No(2)
m,s
m-1=4(s-1)
m+6=2s+9
eq 2-eq1
s=3
10 years agoHelpfull: Yes(0) No(0)

A year ago,Mohit was four time his son"s age.In six years,his age will be 9 more than twice his son age.what is the present age of son?

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