3i-Infotech Company Numerical Ability Time Distance and Speed

Ramakanth drives 150 kilometres to the railway station in 3 hours and 20 minutes. He returns from the railway station to the starting place in 4 hours and 10 minutes. Let A be the average rate for the entire trip. Then the average rate for the trip of going to the railway station exceeds A, in kilometers per hour, by:

a) 4 b) 5 c) 3 d) 2

Read Solution (Total 1)

Average rate –from starting point to railway station = distance / speed of upward journey = 150 /3 1/3 = 45 km/hour
Average rate for return from railway station to starting place = distance / speed of downward journey = 150/ 4 1/6 = 36 km/hour
Total distance combining upward and return journeys = 300 km
Average rate ‘A' = Total Distance / (Speed of Upward Journey + Speed of Return Journey) = 300 /( 3 1/3 + 4 1/6 )
= 40 km.
So the average rate for trip of going to the railway station exceeds A by 45-40 = 5 km
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