F H W *
E B F
___________

E W H H
C B E C
B L C G
__________

W C A G G H

• approach for question like this , depends on which hints you take,
  like there's a hint in 3rd row, EW(HH) , 2 H's ,lets put value of H=1, first
  (i know, in exam hint was given that "H is even" that made calculation more easier)
  ( other hints are guessing of 5 , 6 , 1 , 0 multiplication, a big no, no with carry , etc).
  for H=1 , what are the multiplications that end in 1 (11,21,31,41,51,61,71), the
  only valid one is 21(7x3), now put value 7 and 3 in place of W and F,
  
  3 1 7
  E B 3
  ________
  E 7 1 1
  
  but value of 7 and 3 , gives wrong multiplication, ok ?
  
  now check for the value 3 and 7 , the new multiplication is
  F 1 3
  E B 7
  _______
  E 3 1 1
  
  for this we are also getting wrong multiplication term in 3rd row,(3,7 viceversa cancel out)
  
  check for 2 , 3 , 5, 6 , 7 , 8, 9 value of H ,
  (guys if you PRACTICE, PRACTICE, PRACTICE , crypt you will come to know only some digits add up and multiply to give to double H in the end of row. do practice. period)
  but do take care of all the(rule) first digit of the multiplication rows, first digit of row can't be 9, 8 ( less frequent i mean)
  ok come to back to question , lets take the value of H =8 ( no ending in 8 , 8 18,28, 38 , 48 , 58 , 68) multiplications will be ( 4x2, (6x3, 9x2), 7x4, 6x8) vice versa respectively )
  check the value of H as done above, for each of the following pairs , the only valid pair is 4x7
  now put
  7 8 4
  E B 7
  ______
  E 4 8 8
  from that we get the value of E must be 5
  now put E=5 and check more
  
  7 8 4
  5 B 7
  ----------
  5 4 8 8
  blah blah-
  3 9 2 0 - -
  ______________
  
  now value of B is also known 3 put that one more time , and check again
  you will get
  7 8 4
  5 3 7
  --------
  fulfilling each and every digit you wish to be there :) ,
  trust me , a bit of practice is all required , i was also a kind of noob in crypt earlier , but now most of them are easily solvable
• 10 years agoHelpfull: Yes(5) No(0)
• 784
  *537
  ---------
  5488
  2352
  3920
  --------
  421008
• 10 years agoHelpfull: Yes(2) No(0)
• from the ques
  W+E+G=G therefore W+E=9
  B+1=W
  L+C=C therefore L=9
  
  now for different value of W, E & B we will check
  FHK
  *E
  ------
  BLCG
  -------
  B | W | E
  1 | 2 | 7
  2 | 3 | 6
  3 | 4 | 5
  the multiplication will be satisfied for B=3,W=4,E=5
  784
  *5
  ------
  3920
  ----
  G=0, C=2
  now chk for
  FHW
  *B
  -------
  CBEC
  
  784
  *3
  -----
  2352
  ------
  
  and finally
  784
  *537
  ------
  5488
  2352
  3920
  -----
  421008
  
• 10 years agoHelpfull: Yes(2) No(0)
• 784*537
  
  first check for first row and unit number
• 10 years agoHelpfull: Yes(0) No(0)
• hint is H is even ........
  this question is asked 31 st aug elitmus exam
  
  784*537
• 10 years agoHelpfull: Yes(0) No(0)
• @Dimple Singh: What is the approach to solve such questions?
• 10 years agoHelpfull: Yes(0) No(0)
• Hi Dimple singh can u explain step by step.
• 10 years agoHelpfull: Yes(0) No(0)