Elitmus
Exam
Category
What is the volume of biggest cone that can be fit in a cuboid of height 12*10*15?
Read Solution (Total 8)
-
- ans:- 125pi
- 10 years agoHelpfull: Yes(6) No(8)
- If we take choose the 12*15 face of cuboid for the base of cone then clearly the radius of the right circular is 6 and height is 10.
Hence volume of the cone is= 1⁄3 πr^2h = 120h - 10 years agoHelpfull: Yes(3) No(2)
- 3 cases are possible of base
1.(12,10)=>diameter=10 and height=15 volume=(1/3)*pi*5^2*15=125pi
2.(10,15)=>""""""""=10 """"""""""=12 volume=(1/3)*pi*5^2*12=100pi
3.(12,15)=>""""""""=12 """"""""""=10 volume=(1/3)*pi*6^2*10=120pi
clearly the biggest cone area will be 125pi. - 10 years agoHelpfull: Yes(3) No(1)
- If can take min(12,10)/2 as radius and height as 15
So ans will be 125π - 10 years agoHelpfull: Yes(2) No(0)
- 12*15*11.6=2088
- 10 years agoHelpfull: Yes(0) No(0)
- 12*10*15 = L*B*H..
1) Taking 12/2=6 as radius and cone will be formed in a vertical way. So height=15, volume of cone = 180pi
2) Taking 10/2=5 as radius and now cone will be formed in a horizontal way,So height=12, volume of cone = 100pi.
So case 1 is the biggest cone, So 180pi is the answer. - 10 years agoHelpfull: Yes(0) No(2)
- three kind of bases are there (10,12) or (12,15) or(10,15);
thus radius and height can be paired as (5,15) or (6,10) or (5,12)
by considering all this surface with(10,12) has maximum volume;
thus,volume=(1/3)*pi*(r^2)*h=125*pi=392.7 - 10 years agoHelpfull: Yes(0) No(0)
- check all cases
best case is
r=15/2
h=12
so, volume= 1/3*pi*r^2*h= 225 pi
- 10 years agoHelpfull: Yes(0) No(1)
Elitmus Other Question