find a probability that a leap year contains 53 sundays

a leap year has 366 days and it has 53 days so

it can be done as follows:

366c53
10 years agoHelpfull: Yes(2) No(1)
2/7
As 366/7 is 52 and remaineder is 2
So 2/7.
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366/7=2 odd days...
2/7 is answer
10 years agoHelpfull: Yes(1) No(0)
no. of days in a weak=7
in 7 days there are two situation
1 sat and sun
2 sun and mon
so, probabilty=2/7
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ANS=2/7
becoz a leap year= 52 weeks and 2 days, now in every week we have 21 sunday
so 52 sundays in 52 weeks and the left two days can be any one of the below
(Monday,tuesday), ( Tuesday,wednesday) (Wednesday, thursday) (Thursday , friday) (Friday,
saturday) (Saturday, sunday) (sunday,monday)
hence out of 7 potions 2 include sunday: ans=2/7
9 years agoHelpfull: Yes(1) No(0)
Leap year have 366 days
and probability of having 53 sundays=28/97
10 years agoHelpfull: Yes(0) No(0)
2/7 as 366 days and remainder comes 2 when it is divided by 7.
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