find a probability that a leap year contains 53 sundays

• 2/7
  in leap yr there is 366 days
  366/7=52 and 2 remainder
  so ans is. 2/7
• 9 years agoHelpfull: Yes(17) No(1)
• a leap year has 366 days and it has 53 days so
  
  it can be done as follows:
  
  366c53
• 9 years agoHelpfull: Yes(2) No(1)
• 2/7
  As 366/7 is 52 and remaineder is 2
  So 2/7.
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• 366/7=2 odd days...
  2/7 is answer
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• no. of days in a weak=7
  in 7 days there are two situation
  1 sat and sun
  2 sun and mon
  so, probabilty=2/7
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• ANS=2/7
  becoz a leap year= 52 weeks and 2 days, now in every week we have 21 sunday
  so 52 sundays in 52 weeks and the left two days can be any one of the below
  (Monday,tuesday), ( Tuesday,wednesday) (Wednesday, thursday) (Thursday , friday) (Friday,
  saturday) (Saturday, sunday) (sunday,monday)
  hence out of 7 potions 2 include sunday: ans=2/7
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• Leap year have 366 days
  and probability of having 53 sundays=28/97
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• 2/7 as 366 days and remainder comes 2 when it is divided by 7.
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