If jam's age in 1994 is half of his grandmother's age. Sum of their birth years is 3844. What will be jam's age in 1999?

• in 1994, let the ages of GM and Jam = 2x , x
  birth yr of GM = (1994 - 2x)
  birth year of Jam = (1994 - x)
  given,
  => 1994 - 2x + 1994 - x = 3844
  => x = 48
  in 1999, the age of Jam = (48 + 5) = 53
  
• 9 years agoHelpfull: Yes(88) No(1)
• let 'g' be grand mother's age in 1994
  jam's age will be g/2 in 1994
  so,their birth years would be 1994-g and 1994-(g/2) respectivally
  so 1994-g+1994-(g/2)=3844
  so g=96 and jam's age is 48 and in 1999 he would be 53years.
• 9 years agoHelpfull: Yes(6) No(0)
• (1994-x)+(1994-2x)=3844
  solving this for x we get , x=48
  in 1999 jam's age will be 53 .
  
• 9 years agoHelpfull: Yes(2) No(0)
• in 1994, j age=x, G age= 2x....So D.O.B.=J=1994-x, G=1994-2x,,On addition A.T.Q.
  3x=3844,,so x=48 in 1994,so 53 in 1999
• 9 years agoHelpfull: Yes(1) No(0)
• here, in 1994 Jam of age=Grandmother age/2
  ie,J=G/2
  G=2J
  (1994-J)+(1994-2J)=3844
  3988-3J=3844
  3J=144
  J=48
  Since,at the end of 1994 Jam's age was 48.
  therefore in 1999 Jam's age is 53.[1994+5=1999, 48+5=53]
  
  ANS:53
  
• 9 years agoHelpfull: Yes(1) No(0)
• 43
  in 1994 jam's age was 38
• 9 years agoHelpfull: Yes(0) No(2)
• 53 in 1999
• 9 years agoHelpfull: Yes(0) No(0)
• Ans is53yr
• 9 years agoHelpfull: Yes(0) No(0)