#include
int main(){
int a=2;
a=a++ + ~++a;
printf("%d",a);
return 0;
}

• a++, here it is post increment so it takes value as 2 then it will increments.
  ++a, here it is pre increment so it increments first hence value is 4 and ~4 will be -4-1=-5 then a=2+(-5)=-3
  so it will print -3.
• 10 years agoHelpfull: Yes(9) No(4)
• result is 0
• 10 years agoHelpfull: Yes(7) No(3)
• ans=-3
  2+~4
  2+(-4-1)=2-5
  =-3
• 10 years agoHelpfull: Yes(4) No(1)
• it will give -1 as output, as ~++a= -(++a)+1.
  so, a++ + ~++a= 2+~4= 2+(-4+1)=-1
• 10 years agoHelpfull: Yes(3) No(0)
• a++ is 3
  ++a,here first increment then then take value i.e 4
  3+4=7
• 9 years agoHelpfull: Yes(1) No(1)
• first we have to evaluate from right to left.so,
  a=a++ + ~++a=>a=3 + -4=-1(~3=-3-1=-4).
  so post increment of a will increment after assigning -1 to variable a.
  finally it will print 0.
  
• 9 years agoHelpfull: Yes(1) No(1)
• can u plz explain it
  
• 10 years agoHelpfull: Yes(0) No(0)
• the ++a value may be 4 because a=2 is incremented by a++
• 10 years agoHelpfull: Yes(0) No(3)
• answers is 0
• 10 years agoHelpfull: Yes(0) No(2)
• it will give 0 .
• 10 years agoHelpfull: Yes(0) No(2)
• a=2-4 = -2
• 10 years agoHelpfull: Yes(0) No(2)
• Answer is 0.
• 10 years agoHelpfull: Yes(0) No(2)
• first it will increase value i.e ++a is 3 ,~3=-4,
  now 4-4=0..
  so ans is 0.
  
• 9 years agoHelpfull: Yes(0) No(1)
• 13 is answer.
• 6 years agoHelpfull: Yes(0) No(0)