George does 3/5 of a piece of work in 9 days. He then calls paul and they finish the work in 4 days. How long would paul take to do the work by himself?
1. 28
2. 35
3. 30
4. 32

• george 1 day work=1/15
  let pau 1 day work be 1/x
  work to be done=1-3/5=2/5
  then,a/c
  4(1/15+1/x)=2/5
  =>x=30
  i.e:- 3)30
• 9 years agoHelpfull: Yes(54) No(0)
• 3.30 days
  gorge: does 3/5 th in 9 days
  in 1 day he can do 1/15
  so in 4 days he can do =4/15
  :. total work done by gorge =3/5+4/15=13/15
  
  work left= 1-13/15=2/15
  
  which is done by paul in 4 days so paul can do 2/15*4 in 1 day=1/30
  :. paul will take 30 days to do the job himself
• 9 years agoHelpfull: Yes(38) No(4)
• George does 3/5 work in 9 days..
  So his 1 day's work=3/(9*5)=1/15
  
  Rest of work=1-3/5=2/5
  2/5 work is done by them in 4 days..
  so in 1 day work is=2/(5*4)=1/10
  
  Work done only by paul=1/10-1/15=1/30
  
  i.e Paul himself done the work in 30 days...Ans
• 9 years agoHelpfull: Yes(26) No(0)
• George can do 1/15 of work in 1 day,
  let Paul do 1/p in 1 day,
  
  9*1/15+4*(1/15+1/b)=1
  
  1/b=1/30 means Paul can do 1/30 work in a day so he can finish
  work in 30 days
• 9 years agoHelpfull: Yes(4) No(0)
• g can do it in=3/5*1/9=1/15
  g+p=1/4*2/5=1/10
  p=1/10-1/15=1/30
  so p can do it in 30 days
• 9 years agoHelpfull: Yes(3) No(0)
• paul will take 30 days
• 9 years agoHelpfull: Yes(3) No(4)
• Let total job=1; Gorge do 3/5 in 9 days.then in one day he can complete 3/9*5=1/15.then in 4 days he do 5/15.after completion of george the task remain 1-3/5=2/5.then paul do in 4 days=,(2/5)-(4/15)=2/15...then the total task will be completed in 4*15/2=30 days
• 9 years agoHelpfull: Yes(2) No(0)
• George will take 15 days to do the work alone (3/5x =9days)
  remaining work =1 - 3/5 = 2/5
  George will take 45/2 days to do the remaining work alone
  both can do it in 4 days
  Paul can do it alone in 1/4 - 2/45 (reciprocal)
  180/38 for 2/5 part
  for complete work = (180*5)/(38*2)=11.8 days
• 9 years agoHelpfull: Yes(2) No(3)
• 30 ans bye
• 9 years agoHelpfull: Yes(1) No(2)
• answer 30 days
  in 4 day paul completes 6/45 work so 30 days for whole work
• 9 years agoHelpfull: Yes(1) No(0)
• George (3/5)x -->9. so,complete work(x) in 15days
  george+paul 1-(3/5)=2/5 work in 4 days.both can do complete work in 10 days.
  (1/15)+(1/p)=1/10 ,p=30
  paul can complete it in 30 days alone
• 9 years agoHelpfull: Yes(1) No(0)
• George work in 1 day =1/15
  let Paul do 1/p in 1 day,
  
  9*1/15+4*(1/15+1/b)=1
  
  1/b=1/30 means Paul can do 1/30 work in a day so he can finish
  work in 30 days
• 9 years agoHelpfull: Yes(0) No(0)
• George 9 days work is 3/5.
  George 1 day work is (3/5)/9 = 1/15.
  Total work is 1. Remaining work is 1-3/5=2/5.
  George and Paul on day work is 1/10.
  Paul one day work is 1/30.
  So total work completed by Paul in 30 days
  Ans is 30.
• 9 years agoHelpfull: Yes(0) No(0)
• 30 DAYS
  9 days work 3/5
  1 day wrk=3/(5*9)=1/15work
  now
  remaining work=1-3/5=2/5work
  george+paul 4days work=2/5
  4(1/15+x)=2/5
  x=1/30 work
  total days teken by paul=30 days
• 9 years agoHelpfull: Yes(0) No(0)
• paul will take 30 days.
  
• 9 years agoHelpfull: Yes(0) No(0)
• if 3/5th of the work done in 9 days
  then remaining 2/5th can be done in 6 days..total work will be completed in 6+9=15 days..
  given,
  he and paul finished the work in 4days,if the work is done by the george only he takes-6days..
  so remaining 2 days work done by paul..
  4days work of george=2days work of paul...therefore his efficiency is 1/2..
  he can complete the 15 days of work in 30 days....
• 9 years agoHelpfull: Yes(0) No(0)