(753 x 753 + 247 x 247 - 753 x 247)/ = ?
(753 x 753 x 753 + 247 x 247 x 247)

• if x=753, y=247
  then (x^2+y^2-xy)/(x^3+y^3) = 1/(x+y) = 1/1000 = .001
• 10 years agoHelpfull: Yes(21) No(0)
• a^2-ab+b^2a^3+b^3=1/a+b=1/753+247=1/1000
  
• 10 years agoHelpfull: Yes(3) No(1)
• ans=1000 a^3+b^3=(a+b)(a^2+b^2-ab)
• 10 years agoHelpfull: Yes(2) No(1)
• let,x=753 and y=247 then we get
  =(x^2+y^2-xy)/(x^3+y^3)
  =1/(x+y) //we know;x^3+y^3=(x+y)*(x^2-xy+y^3)
  =1/(753+247)=1/1000
  =0.001
  
• 10 years agoHelpfull: Yes(2) No(0)
• Given problem a^2+b^2-ab/a^3+b^3= 1/a+b =1/1000= 0.001
• 10 years agoHelpfull: Yes(1) No(0)
• sorry it should be in the form of 1/a+b
  a=753
  b=247
  1/1000=.001 Ans
• 10 years agoHelpfull: Yes(1) No(0)
• (753*753+247*247-753*247)/(753*753*753+247*247*247)
  here 753=a;247=b
  so,
  (a^2+b^2-ab)/(a^3+b^3)=1/(a+b) [a^3+b^3=(a^2+b^2-a*b)(a+b)]
  =1/1000 ans..
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• simple 753-247=506 Ans
• 10 years agoHelpfull: Yes(0) No(1)
• a^2+b^2-ab/a^3+b^3= 1/a+b =1/1000= 0.001
• 10 years agoHelpfull: Yes(0) No(0)
• let 753=a 247=b then from above question we get a^2+b^2-ab/a^3+b^3
  hen we get the solution as a^2+b^2-ab/a+b(a^2+b^2-ab)=1/a+b=1/753+247=1/1000
• 10 years agoHelpfull: Yes(0) No(0)
• a^3+b^3=(a+b)(a^2+b^2-ab)
  so ans will be 1/1000
• 10 years agoHelpfull: Yes(0) No(0)
• a^3+b^3 =(a+b)(a^2-ab+b^2)
  ans: 753+247=1000
• 10 years agoHelpfull: Yes(0) No(0)
• (a^3)+(b^3)=(a+b)(a^2-a*b+b^2)
  
  = 1/(753+247)
  =1/1000
• 10 years agoHelpfull: Yes(0) No(0)
• formula (a^2-ab+b^2)/(a^3+b^3)=1/(a+b)
  so here a=753,b=247
  
  ans=1/(753+247)=0.001
  
• 10 years agoHelpfull: Yes(0) No(0)
• 1/1000=0.001
  a^3+b^3=(a+b)(a^2+b^2-ab);
  implies: (753^2+247^2-753*247)/(753^3+247^3)=1/(a+b)=1/1000
• 10 years agoHelpfull: Yes(0) No(0)
• if a=753 , b=247 then the question is in the form
  (a^2+b^2-ab)/a^3+b^3
  
  we can write a^3+b^3 as (a+b)(a^2+b^2-ab)
  
  which gives us 1/(a+b) ,=1/1000
• 5 years agoHelpfull: Yes(0) No(0)