There is a 4 inch cube painted on all sides. This is cut into no of 1 inch cubes. What is the no of cubes which have no painted sides.

• 8 cubes.
  
  The original cube is cut into 64 pieces. Removing all cubes from any two opposite pairs of faces leaves total 32 cubes, as one face contains 16 cubes each. It can be seen that in the remaining two layers, only four each from each layer have no sides painted. So total = 2*4=8 cubes.
• 15 years agoHelpfull: Yes(17) No(7)
• no painted cube formula=(n-2)^3
  since it is 4X4 cube so n=4;(4-2)^3=2^3=8
• 9 years agoHelpfull: Yes(8) No(1)
• total no of cubes = 64 cubes
  3 Face painted = 8 cubes
  2 Face painted = 24 cubes
  1 Face painted = 24 cubes
  So, NO Face painted will be = [64-(8+24+24)] = 8 cubes
• 9 years agoHelpfull: Yes(7) No(0)
• 4
• 15 years agoHelpfull: Yes(3) No(11)
• To be exact, there will be 8 small cubes with 3 faces painted, 24 small cubes with 2 faces painted, 24 small cubes with 1 face painted and 8 small cubes with no faces painted. Try drawing the image on a paper.
• 15 years agoHelpfull: Yes(3) No(3)
• only the 4 cubes which occupied the core portion of the 4inch cube will be totaly unpainted...
• 15 years agoHelpfull: Yes(1) No(5)
• 0 cubes... All cubes are painted.
  
• 10 years agoHelpfull: Yes(0) No(4)
• 8 ans...i solve it oraly....
  
• 10 years agoHelpfull: Yes(0) No(4)
• 8 cubes
• 7 years agoHelpfull: Yes(0) No(0)