If Log2 x - 5 Log x + 6 = 0, then what would the value / values of x be?

• log(2x)-5log(x)+6=0 (given)
  log(2x)-log(x^5)=-6
  log(2x/x^5)=-6 [since log(a)-log(b)=log(a/b)]
  apply anti log
  2/(x^4)=e^-6
  2/(x^4)=2.4788*10^-3
  x^4=806.85
  x=5.3296
  
  
• 11 years agoHelpfull: Yes(8) No(4)
• log2 x - 5 log x + 6 = 0
  (log x) / (log 2) - 5 log x = -6
  (log x) (1/log 2 - 5) = -6
  log x = -6 / (1/log 2 - 5)
  log(x) = -6 / (3.3219 - 5)
  log(x) = 3.575521
  x = 10^(3.575521)
  x ≈ 3763.
• 12 years agoHelpfull: Yes(6) No(10)
• x = e2 or e3
• 11 years agoHelpfull: Yes(6) No(2)