15 people sit arround a round table what are odd against two particular person sit togather

• 6:1
  odds agianst an event=
  (possibilities of event not happenning)/(possibilities of event happening)
  =possibilities that 2 people are not togeather/possi that they are togeather
  = (14!-2*13!)/(2*13!)
  = 6:1
• 10 years agoHelpfull: Yes(14) No(0)
• total 15 people,
  two men must sit together,so that is considered as 1 unit;
  and others are 13 units,
  so total 14 units,
  that can be arranged in (14-1)!=13! ways,
  and other two person can be arranged in two ways,so ans is =13!*2.
• 10 years agoHelpfull: Yes(11) No(6)
• 14!-(13!*2)=12*13!
• 10 years agoHelpfull: Yes(1) No(0)
• Let us consider those 2 particular persons to be 1 unit. Then we have a total of 14 places to choose from. So we can choose that 1 double seat in 14 ways and the two people can interchange their own seats as well. So 14*2 is the answer.
• 10 years agoHelpfull: Yes(0) No(9)