) A person climbed a hill which was 200m high. The average speed while climbing was 24 m/sec and while coming down it was 30m/sec. What is the average speed (in kmph) of his journey?
A. 36 B. 56
C. 76 D. 96

• average speed = 2d/(d/x +d/y) = 2*x*y/(x+y)
  
  = 2*24*30 / (24+30) m/s
  
  = 2*24*30/54 * 18/5 km/h
  
  = 96 km/h
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• AVG SPEED= (2*S1*S2)/(S1+S2)
  =80/3
  TO CONVERT IN KMPH (80/3)*(18/5)
  =96
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• 96
  avg speed=2xy/x+y...
  2*24*30/54=80/3m/s
  80/3*18/5 = 96km/hr
  
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• avg speed=2*24*30/24+30
  1440/54=80/3m/s
  80/3*18/5=96km/hr
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• convertion: 24 m/s=24*(18/5)=86.4 kmph
  30m/s=30*(18/5)=108 kmph
  avg speed when distance is same = (2*x*y)/(x+y)
  avg speed=(2*86.4*108)/(86.4+108)=18662.4/194.4
  avg speed = 96 kmph
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• for one way on climbinf to the hills...it take 25/3 sec
  ffor returning from hills it take 200/30 that is 20/3 sec...
  so total time taken will be 45/3=15 sec that is average time so distance =velocity *time...
  we 400/15=80/3*18/5=96 kmph
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• 200/24+200/30=45/3,total distance=200+200=400,aver speed=400*3/45 m/sec=400*3/45*18/5=96 kmph
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• 400/[(200/24)+(200/30)]=2*30*24/54=80/3 m/s
  80*60*60/3000=96 km/hr
  
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