f(x)=1+x+x^2+....+x^6.
the remainder when f(x^7) is divided by f(x):
1)none
2)6
3)0
4) 7

• put x=0
  so f(x)=1
  f(x^7)=1
  1/1=0
  so 0 is answer
• 9 years agoHelpfull: Yes(3) No(5)
• given: f(x)=1+x+x^2+x^3+x^4+x^5^+x^6
  let x=1
  i.e : f(1)=1+1+1+1+1+1+1=7
  f(x^7)=(1)+(1)+(1^14)+.... =7
  so, f(x^7)/f(x)=7/7=1
  answer is : 1
• 9 years agoHelpfull: Yes(3) No(8)
• 7 take log u will get the ans
• 9 years agoHelpfull: Yes(2) No(0)
• ans given by TCS openseesame is 7...pls tell how it is 7....
• 9 years agoHelpfull: Yes(1) No(1)
• remainder = 0
• 9 years agoHelpfull: Yes(0) No(3)
• By substituting the different values of x. The numerator will be the multiples of denominator. Thus the quotient remains changing, but remainder will be constant.
  i.e remainder is 0.
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 0
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• put x=1 7/7=0
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 7 by taking log
• 8 years agoHelpfull: Yes(0) No(0)