Given is series 1,2,3,7,7,22,15,67,…,what number will come immediately before 63?

• 
  1,2,3,7,7,22,15,67,…
  its combination of two alternate series
  
  1,3,7,15,31,63,127 => next=(pre*2+1)
  2,7,22,67,202,307 => next no.=(pre*3+1)
  
  series is 1,2,3,7,7,22,15,67,31,202,63,307
  
  so, 202 comes immediately before 63.
• 9 years agoHelpfull: Yes(96) No(0)
• 1,2,3,7,7,22,15,67,.........
  let 1,3,7,15,....... the series follows as difference of multiples of 2 i.e
  3-1=2
  7-3=4
  15-7=8
  31-15=16
  63-31=32
  .........
  let 2,7,22,67,........ series follows the difference if multiples of 3 with 5,15,45,135,........... i.e
  7-2=5
  22-7=15
  67-33=45
  202-67=135
  .........
  so the further numbers of series are 1,2,3,7,7,22,15,67,31,202,63,......
  therefore answer is 202
• 9 years agoHelpfull: Yes(2) No(0)
• 1,2,3,7,7,22,15,67,…
  its combination of two alternate series
  
  1,3,7,15,31,63,127 => next=(pre*2+1)
  2,7,22,67,202,307 => next no.=(pre*3+1)
  
  series is 1,2,3,7,7,22,15,67,31,202,63,307
  
  so, 202 comes immediately before 63.
• 9 years agoHelpfull: Yes(1) No(7)
• CP? I did not understand your steps.better luck next time.
• 9 years agoHelpfull: Yes(0) No(0)
• 1,2,3,7,7,22,15,67....
  3=1+2^1
  7=3+2^2
  15=7+2^3=31
  so next no wii be=31+2^4=ans
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1 2 3 7 7 22 15 67
  combination of two series 1 3 7 15.....&2 7 22 67 ...............
  1st series 1*2+1=3
  3*2+1=7
  7*2+1=15
  15*2+1=31
  31*2+1=63
  2nd series 2 7 22 67
  2*3+1=7
  7*3+1=22
  22*3+1=67
  67*3+1=202
  ultimate series 1 2 3 7 7 22 15 67 31 202 63
  ans=63
• 9 years agoHelpfull: Yes(0) No(0)