The ratio b/w the ages of two persons is 6:5.and sum of there ages is 77 then how many years later there ratio becomes 8:7?
We all know that Arya Bhatta is the greatest mathematics belongs to India . When his daughter Mayabati was in her teen age he discovered a problem. At that time the age of Mayabati is a prime number, let that age is a. After some years her age becomes b. then Arya Bhatta was able to solve that problem with the help of his daughter Mayabati. If a-b=5 & product of a& b is 26 then what is the sum of two squares?
A)77 b) 45 c)89 d)67

• a-b=5
  ab=26
  a^2+b^2=?
  we know that,(a-b)^2=a^2+b^2-2ab
  (5)^2=a^2+b^2-2(26)
  25=a^2+b^2-52
  a^2+b^2=25+52
  a^2+b^2=77
  Ans:77
• 10 years agoHelpfull: Yes(29) No(1)
• 6x:5x
  since sum of age=77
  6x+5x=77
  therefore x=7
  the new age is 8x:7x=56:49
  the oder age is 6x:5x=42:35
  56-42=14
  hence after 14 years
• 10 years agoHelpfull: Yes(22) No(1)
• sum of their ages=77
  6x+5x=77
  therefore x=7
  the new ratio is 8x:7x=56:49
  the old ratio is 6x:5x=42:35
  56-42=14 (or) 49-35=14.
  hence after 14 years :)
• 10 years agoHelpfull: Yes(4) No(2)
• ans:77
  a-b=5
  a*b=26
  (a-b)^2=a^2+b^2-2ab
  (5)^2=a^2+b^2-2(26)
  25+52=a^2+b^2
  a^2+b^2=77
  
• 10 years agoHelpfull: Yes(1) No(1)
• 6:5=77
  6x+5x=77
  11x=77
  x=7
  after some yrs ratio will be 8:7
  8x,7x
  8(7)-6(7)=14
  7(7)-5(7)=14 therefore after 14yrs ratio is 8:7
  
  a-b=5, ab=26, a^2+b^2=?
  (a-b)^2= a^2+b^2-2ab
  (5)^2=a^2+b^2*26
  a^2+b^2=77
  
• 10 years agoHelpfull: Yes(1) No(4)
• Practically it is not possible
  a-b=5
  Bcoz b>a
  And also a is prime no
  Then can anyone tell me that whats d value of a????
• 10 years agoHelpfull: Yes(1) No(0)
• a-b=5
  ab=26
  a^2+b^2=(a-b)^2+2ab
  =(5)^2+2*26
  =25+52=77
  hence answer is 77(a)
• 10 years agoHelpfull: Yes(0) No(1)
• a-b=5
  ab=26
  a^2+b^2=(a-b)^2+2ab
  =(5)^2+2*26
  =25+52
  
  =77 :)
• 10 years agoHelpfull: Yes(0) No(1)
• answer 89
  
  77+12 = 89
• 10 years agoHelpfull: Yes(0) No(0)
• all the best to ur tcs exam my best buddies. :)
• 10 years agoHelpfull: Yes(0) No(0)
• a^2+b^2=(a-b)^2 + 2ab
  = 5^2 + 2*26
  = 25 + 52
  = 77
• 10 years agoHelpfull: Yes(0) No(0)
• 1->after 14 yrs
  2->(a)^2+(b)^2=77
• 10 years agoHelpfull: Yes(0) No(0)
• 6x+5x=77
  X=7
  8*7:7*7
  56:49
  6*7:5*7
  42:35
  So 56-42=14yrs
  49-35=14yrs
  Ans=14yrs
• 10 years agoHelpfull: Yes(0) No(0)
• 1) 14years
  2) a^2+b^2=77
• 10 years agoHelpfull: Yes(0) No(0)
• as it is in ratio...so 6x and 5x
  then...sum of their ages ...x+y=77.............(1)
  so, (6x+y)/(5x+y)=8/7.............(2)
  on solving 1,2 get answer...
• 10 years agoHelpfull: Yes(0) No(0)
• a-b=5 &ab=26;
  (a-b)^2=a^2+b^2-2ab
  25=a^2+b^2-52
  a^2+b^2=77
• 10 years agoHelpfull: Yes(0) No(0)