TCS Company Numerical Ability Number System

123^123! what is the late two digit

Read Solution (Total 4)

TCS Other Question

The last digit of the expression 4+92+43+94+45+96+…….+499+9100 is ? when (1!)^1!+(2!)^2!+(3!)^3!+...............(100!)^100! is divided by 5,the remainder obtained is?

a. 2
b. 0
c. 4
d. none of these