A class of 100 students 24 of them are are girls and 32 are not .which base am i using?

• if base be b then
  
  24 are girls so rest 32 are boys
  100 = 24 + 32
  => 1*b^2 + 0*b^1 + 0 = (2b+4) + (3b+2)
  => b^2 - 5b -6 = 0
  => (b-6)*(b+1) = 0
  => b = -1,6
  base can't negative
  so, b = 6
• 10 years agoHelpfull: Yes(40) No(2)
• how u got b^2-5b-6=0??
• 10 years agoHelpfull: Yes(1) No(0)
• Let the base be X.
  
  Therefore
  (X*X + X*0 + 0) = (2*X +4) + (3*X + 2)
  X*X = 5*X + 6
  X*X - 5*X -6 = 0
  (X-6)(X+1) = 0
  
  Therefore base is 6
  
• 10 years agoHelpfull: Yes(1) No(0)
• @vignesh:-
  take b=10 and subtitute in b^2-5b-6 you'll get 100=24+32.
  We have to get a equation so as to get 100=24+32, so thats how u got it
• 10 years agoHelpfull: Yes(0) No(0)
• 24+36 = 100 means 6
• 10 years agoHelpfull: Yes(0) No(5)