If P(x) = ax4+bx3+cx2+dx+e has roots at x = 1, 2, 3, 4 and P(0) = 48, what is P(5)

• x=1,2,3,4 are the roots of equation P(x),
  P(x)=(x-1)*(x-2)*(x-3)*(x-4)
  p(x)=x^4-10x^3+35x^2-50x+24
  P(0)=48 means cofficient should be 48 so
  P(x)=2*p(x)=2x^4-20x^3+70x^2-100x+48
  p(5)=48
  Ans 48
• 10 years agoHelpfull: Yes(2) No(0)
• x=1,2,3,4 are the roots of equation P(x),
  P(x)=(x-1)*(x-2)*(x-3)*(x-4)
  p(5)=(5-1)*(5-2)*(5-3)*(5-4)
  =4*3*2*1
  =24
  Ans. 24
  
• 10 years agoHelpfull: Yes(1) No(1)