1122^(!1122).last digit..??

• 6 ans
  In 1122! anywhere because 2*5 it gives no of zeros so when divided by 4 it give remainder 0.
  base unit 2 is even so last digit will be 6
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• 2^4=6(unit digit)
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• First of all the question will be 1122^(1122!)
  1122! can be viewed as 4*n i,e 4*(278*1121!)
  and we know (any digit)^4n will have the last digit same as the digit^4 will have.
  So, 2^4 gives 16 i,e 6 as last digit,
  so 1122^(1122!) will have 6 as last digit.
  
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• Even power even is 76
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• Ans:4.
  divide 1122 by 4. Remainder is 2.Thus the last digit will be = (last digit of 1122)^(remainder obtained by dividing 1122 by 4) = (2)^2=4.
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