CAT
Exam
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a and b together can complete a job in 8 days.b and c alone can complete the same job in 12 days.a and b works for 4 days,a leave.b continues for 2 more days and b leaves.c start working and finish the job.how many days did c require?
Read Solution (Total 3)
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- ns:4days
here consider the lcm 72,therfore total work is 72
a,b and c complete by 8 days
a,b,n c 's1 days work is 72/8=9units
b and c 's 1 day work is 72/12=6units
now a and b work 4 days ,so 4×9=36units
then remaining work is 72-36=36units
now b continuos for 2 days
then remaining work is 36-(6×2)=24units
c's 1 day work is 6units
so 24/6=4days
c can complete complete the work in 4 days - 10 years agoHelpfull: Yes(2) No(0)
- 4 days
half work by a and b
1/6 by b
1/3 left for c
so it completes in 4 days - 10 years agoHelpfull: Yes(1) No(0)
- 1/a +1/b =1/8
1/b=1/12
1/c=1/12
1-4*(1/8)=1/2
1/2-2*(1/12)=4/12=1/3
(1/3)/(1/12)=4 - 7 years agoHelpfull: Yes(1) No(0)
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