a and b together can complete a job in 8 days.b and c alone can complete the same job in 12 days.a and b works for 4 days,a leave.b continues for 2 more days and b leaves.c start working and finish the job.how many days did c require?

• ns:4days
  here consider the lcm 72,therfore total work is 72
  a,b and c complete by 8 days
  a,b,n c 's1 days work is 72/8=9units
  b and c 's 1 day work is 72/12=6units
  now a and b work 4 days ,so 4×9=36units
  then remaining work is 72-36=36units
  now b continuos for 2 days
  then remaining work is 36-(6×2)=24units
  
  c's 1 day work is 6units
  so 24/6=4days
  c can complete complete the work in 4 days
• 10 years agoHelpfull: Yes(2) No(0)
• 4 days
  half work by a and b
  1/6 by b
  1/3 left for c
  so it completes in 4 days
• 10 years agoHelpfull: Yes(1) No(0)
• 1/a +1/b =1/8
  1/b=1/12
  1/c=1/12
  1-4*(1/8)=1/2
  1/2-2*(1/12)=4/12=1/3
  (1/3)/(1/12)=4
• 8 years agoHelpfull: Yes(1) No(0)