main()
{
int i=5,j;
j = i++ + ++i + ++i + ++i;
printf("%d",i);
}

• first it will increment will be pre-increment
  i.e.,their is 3 pre-increment so the value of j=8+8+8+8=32
  and the value 32 is stored in j.
  then it will be post-increment the value is 9 and is stored on i.
  the ans is i=9
• 9 years agoHelpfull: Yes(17) No(3)
• given I=5;
  I++ means I=5 after perform the operation it becomes I=6
  ++I means I=7
  ++I means I=8
  ++I means I=9
  so current value of I is 9
• 9 years agoHelpfull: Yes(11) No(1)
• ans-29
  j=8+8+7+6=29
• 9 years agoHelpfull: Yes(10) No(11)
• j = i++ + ++i + ++i + ++i
  8 + 8 + 7 + 6
  = 29
  then i will be post incremented hence i = 9
• 9 years agoHelpfull: Yes(6) No(4)
• 26 5+6+7+8
• 9 years agoHelpfull: Yes(5) No(6)
• 9 answer 5 6 7 8 9
• 9 years agoHelpfull: Yes(2) No(3)
• j=i++ + ++i + ++i + ++i
  j=5 +6+7+8 j=26
  i=8
• 9 years agoHelpfull: Yes(2) No(8)
• I am sorry the precedence doesn't have anything to do with it.
  Ans:j=29 and i=9;
• 9 years agoHelpfull: Yes(1) No(1)
• ans is 8 because if ++i means first i value will be incremented for example
  i=1;
  j=++i;
  then ans is i=2,j=2
  in the same way if i++ means first i value is printed and then i value is incremented for the i=1;j=i++; then i=2,j=1 soo in the same way my answer is i=8,j=21
• 9 years agoHelpfull: Yes(1) No(3)
• ++i will increment the value of i, and then return the incremented value.
  
  i = 1;
  j = ++i;
  (i is 2, j is 2)
  i++ will increment the value of i, but return the original value that i held before being incremented.
  
  i = 1;
  j = i++;
  (i is 2, j is 1)
  from the above example my answer is 9
• 9 years agoHelpfull: Yes(1) No(1)
• J=5+6+6+6=23. I=24
  
  
• 9 years agoHelpfull: Yes(1) No(1)
• j=5+7+8+9=29 i=9
• 9 years agoHelpfull: Yes(1) No(1)
• i=5,
  there are three pre increment which makes i=8
  and one post increment which makes i=9
• 9 years agoHelpfull: Yes(1) No(0)
• (5++)+(++6)+(++7)+(++8)=5+7+8+9=29
• 9 years agoHelpfull: Yes(1) No(0)
• Answer: i=9.
  i++, here it is post increment so it takes value as 5 then it will increments.
  ++i, here it is pre increment so it increments first hence value will be 7 because one operation already done(first i++) so j=5+(1+6)+8+9=29
  hence last value of i is 9.
• 9 years agoHelpfull: Yes(1) No(0)
• j=8+8+8+8
  i=9
• 9 years agoHelpfull: Yes(1) No(1)
• 26
  execution left to right
  op: r to l
  6+7+8+8
• 9 years agoHelpfull: Yes(0) No(3)
• i=9;
  and j=29; b'cause j=8+6+7+8;
  ++i has more priority comared to i++
• 9 years agoHelpfull: Yes(0) No(1)
• since value of i is to be printed it will be 9.(after going through 4 increments)
• 9 years agoHelpfull: Yes(0) No(0)
• in this problem firstly 3 times pre increment operator increase value of i then after evaluation of j done after that post inc operator evaluated so value of i became 9
• 9 years agoHelpfull: Yes(0) No(1)
• 9
  when 5 will come to i++ it will be 5 only then will get incremented then it will be passed on to ++i and it will become 7 now when it will reach to other ++i will become 8 at last it will 9 when passed on to ++i which is last in given equation.
  Final output will be 9
• 9 years agoHelpfull: Yes(0) No(1)
• 8+8+7+6=29
  bcoz printf priority is from right to left
• 9 years agoHelpfull: Yes(0) No(1)
• there is no error in compilation but it give a wqarning and it can not be run
• 9 years agoHelpfull: Yes(0) No(1)
• i thought answer would be 29...but after executing i found that it was 27
• 9 years agoHelpfull: Yes(0) No(1)
• j=5+6+7+8
  ans=26
• 9 years agoHelpfull: Yes(0) No(1)
• j=i++ + ++i + ++i + ++i;
  execution start from right to left
  so,++i is pre-increment ans is 6 then ++i is also pre-increment ans is 7 then ++i is again pre-increment ans is 8 then finally i++ is post increment ans is 8
  therefore answer is 8 + 8 + 7 + 6=29
• 9 years agoHelpfull: Yes(0) No(1)
• 26. i++ means It will firstly use the value and then increment it. whereas, ++i means firstly it will increment and then use the incremented value.
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is 9
  j=8+8+7+6
  i=8+1=9
  so ans is 9
• 9 years agoHelpfull: Yes(0) No(0)
• j = i++ + ++i + ++i + ++i
  8 + 8 + 7 + 6
  = 29
  then i will be post incremented hence i = 9
  
• 9 years agoHelpfull: Yes(0) No(0)
• 
  ans is 29
  
• 9 years agoHelpfull: Yes(0) No(0)
• i=9 bcz before the assign the value of i in j i incremented 3 times pre-incremented so i become 8 then
  8+8+8+8 i.e 32 will stored in j then i will increment once again i.e post increme and i will bcm 9.
• 9 years agoHelpfull: Yes(0) No(0)
• 5+7+8+8=28
• 9 years agoHelpfull: Yes(0) No(0)
• j=8+8+7+6
  here in last i=8
  after this statement i increase by 1 because of i++
  so i=9
  
• 9 years agoHelpfull: Yes(0) No(0)