What is the value of 44444445*88888885*444444442*44444438/44444448^2

1) 88888883
2) 88888884
3) 88888888
4) 44444443

• actual question is (44444445*88888885*444444442+44444438)/44444444^2.
  then x=44444444
  equation becomes
  =((x+1)*(2x-3)*(x-2)+(x-6))/x^2
  =((2x^2-x-3)(x-2)+(x-6))/x^2
  =(2x^3-4x^2-x^2+2x-3x+6+x-6)/x^2
  =(2x^3-5x^2)/x^2
  =2x-5
  =2(44444444)-5
  =88888888-5
  =88888883
• 9 years agoHelpfull: Yes(63) No(2)