. 2ab5, ab is multiples of 13 and this value perfectly divisible by 25. ab=?

• ANSWER==> 52
  2ab5 is perfectly divisible by 25 so b= 2 or 7
  because as 25/75 must be the last two digits to be divisible by 25
  none of 13's multiple have 7 as unite digit so it must be 2.
  hence b=2
  now 52=13*4
  hence a=5
  so the number becomes 2525
• 9 years agoHelpfull: Yes(17) No(2)
• 2525 is divisible by 25 and 52 is multiple of 13
  so, ab=52
• 9 years agoHelpfull: Yes(7) No(1)
• if we consider multiples of 13, we have 13,26,39,52 & by substituting 52 in place of ab the no. becomes 2525, which is exactly divisible by 25.thus,ab=52
• 9 years agoHelpfull: Yes(3) No(0)
• 52 because it is multiple of 13 and it the whole no is divisible by 25.
• 9 years agoHelpfull: Yes(1) No(2)
• 2ab5 must be divisible by 25, it will be only when tenth place will be either 2 or 7.
  check the rule of divisibility of 13. we find that ab=92
  so no becomes 2925 which is perfectly divisible by 25 as well as 13.
  Enjoy buddy
• 9 years agoHelpfull: Yes(1) No(12)
• ab=(13*4)=52
• 9 years agoHelpfull: Yes(0) No(3)
• ans : ab=52
• 9 years agoHelpfull: Yes(0) No(2)
• 25 or 50 or 75
• 9 years agoHelpfull: Yes(0) No(8)
• 2+A+B+5 =5(multiplier) if a+b=8=(2+6) then condition will be fullfilled.
• 9 years agoHelpfull: Yes(0) No(0)
• For divisibility rule of 25, the last two digit should be multiple of 25. If we put 52 as ab then it is multiple of 13 and also whole number divisible by 25. so ab is 52.
• 9 years agoHelpfull: Yes(0) No(0)
• http://www.academia.edu/8221546/Tcs_aptitude
• 8 years agoHelpfull: Yes(0) No(0)