IBM
Company
Numerical Ability
Permutation and Combination
36 identical chairs must be arranged in rows with the same number of chairs in each row. Each row must contain at least three chairs and there must be at least three rows. The row is parallel to the front of the room. How many different arrangements are possible? Pick one of the choices
a) 2 b) 4 c) 5 d)6 e) 10
Read Solution (Total 8)
-
- (3,12),(4,9),(6,6)(9,4),(12,3)
no of diff. arrangement=5 - 10 years agoHelpfull: Yes(39) No(0)
- 1) 3 chair in each row total rows=12
2) 4 chair in each row total rows=9
3) 6 chair in each row total rows=6
4) 9 chair in each row total rows=4
5) 12 chair in each row total rows=3
therefore ans is 5 - 10 years agoHelpfull: Yes(27) No(3)
- answ is 5 .... (3,12)(4,9)(6,6)(9,4)(12,3)
because of the given condition (18,2) is wrong , 3 chairs n rows minimum so. - 10 years agoHelpfull: Yes(3) No(0)
- Ans:5
when row is 3: 3*12=36
when row is 4: 4*9=36
when row is 6: 6*6=36
when row is 9: 9*4=36
when row is 12: 12*3=36 - 10 years agoHelpfull: Yes(3) No(1)
- 6is write ans
- 10 years agoHelpfull: Yes(2) No(25)
- for salaka,in question atleast 3 rows is given we cant take 2 rows,(9,4)(4,9),(3,12)(12,3)(6,6);
ans is 5 - 10 years agoHelpfull: Yes(2) No(1)
- (B) is the corrct answer
- 10 years agoHelpfull: Yes(1) No(13)
- answer is 6.
(3 chairs,12 rows)
(4 chairs,9 rows)
(6 chairs,6 rows)
(9 chairs,4 rows)
(12 chairs,3 rows)
(18 chairs,2 rows) - 10 years agoHelpfull: Yes(1) No(40)
IBM Other Question