3 trucks A, B, C. A loads 10 kg/min. B loads 13 1/3 kg/min. C unloads 5kg/min. If three simultaneously works then what is the time taken to load 2.4 tones?

• work done in 1 min =10+40/3-5=55/3 kg/min
  for 1 kg=3/55 min
  for 2.4 kg=3/55*2400=130mins=2hrs,10min
• 10 years agoHelpfull: Yes(43) No(6)
• Soorry I had done mistake
  In 1 min A+B+C upload 10+40/3-5=55/3 kg for 2.4 ton time taken=(3/55)*2.4*1000
  =130.9 min= 2 hr 11 min
• 10 years agoHelpfull: Yes(13) No(3)
• 1 ton =1000 Kg
  
  work done in 1 min=10Kg/min+40/3 Kg/min-5Kg/min
  =(5+40/3)Kg/min
  =(55/3)Kg/min
  
  total no of minutes to load 2400Kg=2400Kg/(55/3)Kg/min
  =2400*3/55 min
  =44000 min
  =733 hrs 20 mins
  =30 days 13 hrs and 20 mins
  
  
• 10 years agoHelpfull: Yes(9) No(15)
• Work done in by A,B,C in 1 min=(10+50/3-5)=55/3 kg
  1 ton=1000 kg
  2.4 tones=2.4*1000=2400 kg
  Time taken to load 2400 kg=3/55*2400=130.90 min= 2 hrs 10 min 54.5 seconds
  
• 10 years agoHelpfull: Yes(5) No(1)
• (A+B+C)'s 1 min. work=(1/5)-(1/10+3/40) {as C is unloading the truck and A&B are loading it}
  =1/40
  So, A,B &C will finish the work in (40/1)=40 minutes
  now, 2.4 tones=2.4*1000 kg
  =2400 kg
  Thus, time taken to load 2.4 tones= 40*2400 minutes
  = 96000 minutes
  ~ 160 hours.
• 10 years agoHelpfull: Yes(3) No(4)
• Here the Solution..
  1 min A+B+C upload (10+40/3-5)=55/3 kg.[cause here,A and B loads but C unloads]
  now for 2.4 ton time taken=[(3/55)*2.4*1000]
  =130.9 min(approx)
  = 2 hr 11 min
• 10 years agoHelpfull: Yes(3) No(1)
• In 1 min A+B+C load 10+131/3 +5=176/3 kg
  So for 2.4 tones time taken=(3/175)*2.4*907 min
• 10 years agoHelpfull: Yes(1) No(4)
• About 6.4 hour
• 10 years agoHelpfull: Yes(1) No(5)
• A loads 1min=10kg& B loads 1min=40/3kg& c unloads 1min=5kg then A+B's 1min=70/3 kg& c unloads 5kg /min......so 1min=70/3 -5=15.33...then2.4tones means 2400kg required time==2400/15.33=158min.
• 10 years agoHelpfull: Yes(1) No(2)
• 1 min work by A+B+C=10+13.33-5=18.33
  so 3 min work will be 55kg.
  now 2400/55=43.64(aprox)
  so ans will be 43.64*3=130.9(approx 131 min)
  so ans will be 2 hour 11 min(approx)
• 10 years agoHelpfull: Yes(1) No(1)
• work done in 1 min =10+40/3-5=55/3 kg/min
  for 1 kg=3/55 min
  for 2.4 ton
  =3/55*2400=130mins=2hrs,10min
• 10 years agoHelpfull: Yes(1) No(0)
• 156 MIN ALREADY I TOLD THE PROCESS JUST MISTACK THE ANSWER
  156 min is right.
• 10 years agoHelpfull: Yes(0) No(2)
• common load=lcm of 10kg,40/3kg,5kg=40kg
  A will take time to load =40/10=4min
  B will take time to load =40/(40/3)=3 min
  C will take time to unload =40/5=8 min
  so at d end of(4+3+8=15 min),total load loaded=40+40-40=40kg
  so to load 2.4 ton i,(e=2.4*1000kg=2400kg),time taken is:
  (15min/40)*2400=90 min
  
• 10 years agoHelpfull: Yes(0) No(0)