A travels at 40kmph and B travels at 60kmph. They are traveling towards each other and start at the same time. By the time they meet, B would have traveled 120 km more than A. Find the total distance.

• ans:600km
  s=d/t
  let the distance travelled by a=x km
  the distance travelled by b=(x+120) km
  x=40*t
  x+120=60*t
  on solving we get t=6
  x=240,x+120=360
  so total distance=600km
  
• 10 years agoHelpfull: Yes(48) No(1)
• a speed 40kmph then a travel...
  1 hour- 40
  2 " 80
  3 " 120
  4 " 160
  5 " 200
  6 " 240
  ......................
  B speed 60kmph
  then in 1 hour - 60
  2 " 120
  3 " 180
  4 " 240
  5 " 300
  6 " 360
  AFTER 6 HOUR THEY MEET the traven distance is (360-240 =120)
  so total distance is 240+360 =600 ans
• 10 years agoHelpfull: Yes(17) No(2)
• ans 600
  x=40t
  x+120=60t
  on solving t=6
  total distance=(40*6)+(60*6)=600
• 10 years agoHelpfull: Yes(5) No(0)
• 600 km
  x/40=(x+120)/60
  x=240 ; x+120=360 ; total dist= 600
  
• 10 years agoHelpfull: Yes(4) No(0)
• Relative difference b/w them is 20km/hr
  and the 2nd train traveled 120KM more. So divide 120 by 20 we get 6. and multiply 6 with both like 6*40=240 & 6*60=360..Now 240+360=600km.
• 10 years agoHelpfull: Yes(2) No(0)
• let x be distance traveled by A
  then B traveled x+120km
  as they traveled for same time
  then
  (x/40)=(x+120)/60
  on solving it we get
  x=240
  there fore A traveled 240 km & B 360 km
  then total distance is 240+360=600 km
• 10 years agoHelpfull: Yes(1) No(0)
• 600km..
  after 6 hours both A and B met after covering distances by them.
• 10 years agoHelpfull: Yes(1) No(0)
• ans:600km
  let the distance travelled by a=xkm
  and the distance travelled by b=x+120km
  total speed=(40+60)=100kmph
  s=d/t
  d=s*t
  x=40*t
  x+120=60*t
  by solving t=6sec
  now total distance=s*t
  d=100*6
  =600km
  
• 10 years agoHelpfull: Yes(1) No(0)
• distance=(difference in distance*sum of speeds)/(difference in seeds)
  distance=(120*100)/20
  answer is:600
• 10 years agoHelpfull: Yes(1) No(0)
• A-x
  B-x+120
  x/40=(x+120)/60
  x=240
  x+120=360
  total distance=240+360=600km
• 10 years agoHelpfull: Yes(1) No(0)
• A travels at 40kmph and B travels at 60kmph
  after certain time the difference speed is (60-40) = 20kmph
  120km difference will be in (120/20)= 6hrs
  in 6 hrs A will travel 40*6= 240km and B will travel 60*6=360km
  so the total distance is (240+360)=600km
• 9 years agoHelpfull: Yes(1) No(0)
• ans is 600.
  
• 10 years agoHelpfull: Yes(0) No(0)
• 60-40=20....20*6=120 i.e (40+60)*6=600
• 10 years agoHelpfull: Yes(0) No(0)
• Ans 600
  Correct solution...
• 10 years agoHelpfull: Yes(0) No(1)
• let us assume that dis travelled by A is X..then B=X+120
  X/40=(X+120)/60
  X=240
  then the total distance is 600
  
• 10 years agoHelpfull: Yes(0) No(0)
• 360km ans
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• let distance travel by A is X
  and of B is (X + 120)
  as we know T= D/s
  here both start at same time so,
  X/40 = (X+120)/60
  on solving
  we get to know
  A covers 240km
  B covers 360km
  so final is 600km ans.
• 10 years agoHelpfull: Yes(0) No(0)
• A (speed)=40km/hr & B(speed)=60km/hr
  time =constant(both A& B take same time)
  let A cover distance=x & B cover distance=(120+x)( a/q )
  SO 40*(120+X) = 60*X
  we get x=240
  so total distance cover by A&B=x+(120+x)=600
• 10 years agoHelpfull: Yes(0) No(1)
• time is const.
  let distance traveled by A be X
  X/40=X+120/60
  X=240
  X+120=360
  total= 240+360=600km
• 10 years agoHelpfull: Yes(0) No(0)
• let the distance be xkm,then s=d/t
  t=x/40---(1) for A
  For B
  t=120+x/60--(2)
  since by the time they meet b have travelled 120km than A
  equate 1 and 2 and solve
  then x=240km
  120+x=320
  total distance=240+360=600km .so,ans =600km
• 8 years agoHelpfull: Yes(0) No(1)